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Natalija [7]
3 years ago
12

according to the collision theory, for a reaction to be successful, it must have correct orientation of the atoms of the reactan

ts. which of the following must also be true for a successful reaction to occur? a catalyst must be present. the collision must have sufficient energy. the particles must have adequate velocity. reactants must have high molecular mass.
Chemistry
2 answers:
DerKrebs [107]3 years ago
6 0
The collision must have sufficient energy as well.  If sufficient energy is not present the activation energy will not be over come and the bonds in the reactants will not be broken.

I hope this helps.  Let me know if anything is unclear.
igomit [66]3 years ago
6 0

<u>Answer:</u> The correct answer is the particles must have adequate velocity.

<u>Explanation:</u>

According to collision theory, a product is formed only when the collisions between the reactants is effective.

There are 2 factors on which the effective collisions depends:

  • <u>Energy factor: </u>This factor says that the colliding molecules must have energy greater than the threshold energy.
  • <u>Orientation factor:</u> This factor says that the colliding molecules must have a proper orientation at the time of collision.

Velocity is related to kinetic energy by the formula:

E=\frac{1}{2}mv^2

where,

E = kinetic energy of the particle

m = mass of the particle

v = velocity of the particle

So, from this we can say that the velocity of the particles must be sufficient enough for collision to be elastic.

Hence, the correct answer is the particles must have adequate velocity.

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Answer:

6

Explanation:

7 0
3 years ago
Convert 1000mg=__g 1L=__mL 160cm=__mm 1.4km=__m 109g=__kg 250m=__km 80cm=__m 75mL=__L 5.6m=__cm 6.5g=__mg 170.4m=__cm 564Dg=__g
Snowcat [4.5K]

Answer:

1000mg= 1g

1L= 1000 mL

160cm = 1600mm

1.4km= 1400m

109 g = 0.109kg

250m= 0.250 km

80cm= 0.8 m

75mL= 0.075L

5.6m= 560 cm

6.5g= 6500mg

170.4m= 17040 cm

564 Dg = 5640 g

58 dg = 5800 mg

600 L=  0.6 KL

0.0923Km= 92300 mm

Explanation:

1 mg = 1x10⁻³ g

1 g = 1000 mg

1 g = 10 dg

1 g = 1x10⁻³ kg

1 Dg = 10 g

1 dg = 100 mg

1 L = 1000 mL

1 L = 1x10⁻³ KL

1 mL = 1x10⁻³ L

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1 km = 1x10⁶ mm

1 m = 1x10⁻³ km

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5 0
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Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

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Substitute the values into above formula as follows.

E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV

The negative sign indicates that energy is being released.

Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

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