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Travka [436]
3 years ago
5

At time t = 1, a particle is located at position (x, y) = (5, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 11 fi

nd its approximate location at time t = 1.02.
Physics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

Its approx location is (5.18,1.9)

Explanation:

Using F( 5,2) = ( xy-1, y²-11)

= ( 5*2-¹, 2²-11)

= (9,-5)

= so at point t=1.02

(5,2)+(1.02-1)*(9,-5)

(5,2)+( 0.02)*(9,-5)

(5+0.18, 2-0.1)

= ( 5.18, 1.9)

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Answer:

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Explanation:

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3 years ago
How much heat will be needed to warm 187 grams of water from 10 0C to 90 0C?
kvv77 [185]
<h3>Hello there!</h3>

Here, you are looking for the amount of heat put in for water, at a mass of 187 grams, to change by 80 degrees.

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The information given:

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Now just plug everything in to solve.

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5 0
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Dahasolnce [82]

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