Explanation:
36-4/4= 9 m/squared. meter per squared.
acceleration unit is meter per second Square.equation is velocity by time.for average final(36) minus initial(4)
Mass and distance
force /pull of gravity decreases with the increase in separation between the two bodies
the amount of gravity an object possesses is proportional to the mass of that object.
First of all, we need to convert the angular speed from rev/min into rev/s:
The angular acceleration is the variation of angular speed divided by the time:
And this is constant, so we can use the following equation to calculate the angle through which the engine has rotated:
so, 5 revolutions.
The statement about pointwise convergence follows because C is a complete metric space. If fn → f uniformly on S, then |fn(z) − fm(z)| ≤ |fn(z) − f(z)| + |f(z) − fm(z)|, hence {fn} is uniformly Cauchy. Conversely, if {fn} is uniformly Cauchy, it is pointwise Cauchy and therefore converges pointwise to a limit function f. If |fn(z)−fm(z)| ≤ ε for all n,m ≥ N and all z ∈ S, let m → ∞ to show that |fn(z)−f(z)|≤εforn≥N andallz∈S. Thusfn →f uniformlyonS.
2. This is immediate from (2.2.7).
3. We have f′(x) = (2/x3)e−1/x2 for x ̸= 0, and f′(0) = limh→0(1/h)e−1/h2 = 0. Since f(n)(x) is of the form pn(1/x)e−1/x2 for x ̸= 0, where pn is a polynomial, an induction argument shows that f(n)(0) = 0 for all n. If g is analytic on D(0,r) and g = f on (−r,r), then by (2.2.16), g(z) =
Answer:
Explanation:
still water speed is 50 m / 25.0 s = 2.00 m/s or 200 cm/s
In lane 1 the effective speed would be 201.2 cm/s
5000 cm / 201.2 cm/s = 24.85 s
The change is 25.00 - 24.85 = 0.15 s decrease in time
In lane 8, the effective speed would be 198.8 cm/s
5000 cm / 198.8 cm/s = 25.15 s
The change is 25.00 - 25.15 = 0.15 s increase in time
