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Travka [436]
3 years ago
5

At time t = 1, a particle is located at position (x, y) = (5, 2). If it moves in the velocity field F(x, y) = xy − 1, y2 − 11 fi

nd its approximate location at time t = 1.02.
Physics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

Its approx location is (5.18,1.9)

Explanation:

Using F( 5,2) = ( xy-1, y²-11)

= ( 5*2-¹, 2²-11)

= (9,-5)

= so at point t=1.02

(5,2)+(1.02-1)*(9,-5)

(5,2)+( 0.02)*(9,-5)

(5+0.18, 2-0.1)

= ( 5.18, 1.9)

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Which car is harder to stop and why?
kondor19780726 [428]

Answer:

The momentum of bath cars is 40000 Ns which make the difficulty to stop each car in aspect of fprce is the same.

Explanation:

Momentum (P) =mass(m) × velocity (v)

For car A,

                    P = m × v = 1000 × 40 = 40000 Ns

For car B,

                    P = m × v = 4000 × 10 = 40000 Ns

Force (F) = Momentum change(ΔΡ)/ time taken(t)

            F = ΔΡ/t

When stopping the car the momentum changes from 40000 Ns to 0

So momentum change in both cars is the same. So to stop the two cars in a  given time (t) you need the same force, which means you will feel same difficulty.

             

8 0
3 years ago
Read 2 more answers
A Boeing 747 "Jumbo Jet" has a length of 59.7 m. The runway on which the plane lands intersects another runway. The width of the
tia_tia [17]

Answer:

t = 1.48 s

Explanation:

As we know that length of the Boeing plane is

L = 59.7 m

width of the intersection is given as

w = 25.0 m

now we know that deceleration of the plane is given as

a = -5.4 m/s^2

Also the final speed of the plane while it clears the intersection is given as

v_f = 53 m/s

now we have

d = (\frac{v_f + v_i}{2}) t

(25 + 59.7) = (\frac{53 + v_i}{2}) t

also we know that

v_f - v_i = at

53 - v_i = -5.4 t

now we have

84.7 = (\frac{53 + 53 + 5.4t}{2})t

by solving above equation we have

t = 1.48 s

5 0
3 years ago
The relationship between the volume and temperature of a gas was first put forward by the French scientist Jacques-Alexandre-Cés
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Answer:

1 , 2 and , 4 on usa test prep

Explanation:

4 0
3 years ago
a ball (mas .40) is initially moving to the left at 30m/s. After hitting the wall, the ball is moving to the right at 20 m/s. Wh
Step2247 [10]

Answer:

The impulse is -20kg m/s.

Explanation:

given mass of ball =  0.4 kg

The ball is moving towards left with the initial velocity = 30m/s

The momentum in left direction P1 = mv1

= (0.4)(30)

= 12 kg m/s

The given velocity towards right = -20 m/s ( negative sign shows inverse direction)

Momentum towards right, P2 = mv2

P2 = (0.4)(-20)

P2 = -8 kg m/s

The Impulse = change in momentum

= P2 –P1

= -8-12

= -20 kg m/s

6 0
3 years ago
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