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a_sh-v [17]
4 years ago
12

Under what atmospheric condition is fog most often formed in the san joaquin valley?

Physics
1 answer:
GalinKa [24]4 years ago
4 0
It seems that you have missed the necessary options for us to answer this question so I had to look for it. Anyway,here is the answer. The atmospheric condition in which <span>fog is most often formed in the san Joaquin valley is stable stability. Hope this helps.</span>
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A truck driving along a highway road has a large quantity of momentum. If it moves at the same speed but has twice as much mass,
oee [108]

If the truck moves at same speed but twice as much mass, its momentum is increased twice.

Answer:

Explanation:

Momentum is defined as the force experienced by any object for a given time. In other words, it is the measure of the mass and velocity required for a certain motion. So it is determined as the product of mass and velocity of any object.

Momentum = Mass × Velocity.

As momentum is directly proportional to both mass and velocity, increase in any one of these two quantities keeping the other constant will lead to increase in the momentum.

So in the present case, it is stated as speed is kept constant and the mass is increased twice, then the momentum will also increase twice.

New momentum = 2 ×mass × velocity = 2 × old momentum

If the truck moves at same speed but twice as much mass, its momentum is increased twice.

3 0
4 years ago
How do cells use food to make energy and maintain homeostasis?
vladimir1956 [14]

Homeostasis is the state of maintaining steady internal conditions by the living organisms. Cells obtain energy through the process of cellular respiration. It is a metabolic process of conversion of the biochemical energy from the nutrients into adenosine triphosphate (ATP). It also maintains the temperature of the body. The energy produced during this process is used in the cell division and repair of the cells by the breakdown of ATP and maintains homeostasis. They exchange substances with the new cells and also eliminate the wastes thereby maintaining homeostasis.

plz mark me as brainliest :)

7 0
3 years ago
HELP ME ANSWER THIS PLZ I WILL GIVE BRAINLIEST
disa [49]

Answer:

In mitosis, the products are identical to the parent cell, while in meiosis the products are different from the parent cell.

Explanation:

Mitosis replicates DNA at the beginning of the process, so it's always the same, but Meiosis uses a special process called crossing over which causes two chromosomes to swap information, which means that the DNA has changed.

5 0
3 years ago
In induction, what charge does a neutral substance gain compared to the object brought near it?
FromTheMoon [43]

Explanation:

In induction, what charge does a neutral substance gain compared to the object brought near it?

The neutral object gains the same type of charge as the object that touched it because the electrons move from one object to the other (Figure 10.16). Induction is the movement of electrons within a substance caused by a nearby charged object, without direct contact between the substance and the object.

8 0
3 years ago
a length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be
Natali [406]
The equivalent resistance of n resistors connected in parallel is given by
\frac{1}{R_{eq}} =  \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n} (1)

In our problem, the resulting resistance of the 5 pieces connected in parallel is R_{Eq}=2.00 \Omega, and since the 5 pieces are identical, their resistance R is identical, so we can rewrite (1) as
\frac{1}{R_{Eq} }= \frac{1}{2 \Omega}= \frac{1}{R}+ \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   =  \frac{5}{R}
From which we find R= 5 \cdot 2 \Omega = 10 \Omega.

So, each piece of wire has a resistance of 10 \Omega. Before the wire was cut, the five pieces were connected as they were in series. The equivalent resistance of a series of n resistors is given by
R_{Eq}=R_1 + R_2 + ...+R_n
So if we apply it at our case, we have
R_{eq}=R+R+R+R+R=5 R= 5\cdot 10 \Omega= 50 \Omega

therefore, the resistance of the original wire was 50 \Omega.
5 0
3 years ago
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