A planet moves in a circular orbit of radius 4.5x10^15 m with a period of 4
1 answer:
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Answer:
1: 6.18 cm
2: 52.5609 degrees
Explanation:
We have the pendulum speed at the origin, and in that moment, all energy is kinetic, so we can calculate the pendulum energy by:
Ec = 0.5*m*v^2 = 0.5*0.015*1.1^2 = 0.0091 J
Now with that energy, we can calculate the height the pendulum will reach, as in that moment, the kinetic energy is totally converted to gravitational potencial energy:
Eg = m*g*h = 0.0091
0.015 * 9.81 * h = 0.0091
h = 0.0091 / (0.015 * 9.81 ) = 0.0618 m = 6.18 cm
Looking at the image attached, we can see that the pendulum will form a triangle, and one of the cathetus will be the length of the pendulum minus the height it went up, and the hypotenusa will be the pendulum length.
So, we know that the sine of the angle will be the division between the opposite cathetus and the hypotenusa:
sin(angle) = (30-6.18)/30 = 23.82/30 = 0.794 -> angle = 52.5609 degrees
Answer:
a) He found the same value of q/m for different cathode materials.
b) y = , c) v =
Explanation:
In Thomson's experiments he was able to measure the deflection of the light beam under the effect of the magnetic field and with these results find the e / m relationship, which in all cases is the same, therefore the most important conclusion is that the value e E / m is constant for all materials.
b) In the part of the plates the electrons are accelerated by the electric field,
F = ma
- e E = m a
a = - (e/m) E₀
the distance traveled is
X axis
x = v₀ t
the separation of the plates is x = d
t = vo / d
Y axis
y = v_{oy} t + ½ to t²
y = ½ a t²
y =
c) In this case there is a magnetic field B₀ and the electrons have no deflection
F = - e E + e v x B
if there is no deviation F = 0
e E = e v B
v =