All categories

3 years ago

A planet moves in a circular orbit of radius 4.5x10^15 m with a period of 4

Physics

1 answer:

GaryK [48]3 years ago

7 0

Answer:

2.6×10^{10} m/s

Explanation:

there are many students who can not get answer step by step and in required time. so

there are a wats group where you can get your answer by trusted experts.

join this wats up group and be smart.

You might be interested in

Mercury, Mars, and Earth’s moon all show evidence of heavy cratering from meteor impacts while Earth shows much less evidence of

algol [13]

Answer:

Explanation:

4 0

3 years ago

A convex refracting surface has a radius of 12 cm. Light is incident in air (n = 1) and refracted into a medium with an index of

OLga [1]

Answer:

<h2>36cm from the surface</h2>

Explanation:

Equation of refraction of a lens is expression according to the formula given below;

$\dfrac{n_2}{v} = \dfrac{n_1}{u}= \dfrac{n_2-n_1}{R}$

R is the radius of curvature of the convex refracting surface = 12cm

v is the image distance from the refracting surface

u is the object distance from the refracting surface

n₁ and n₂ are the refractive indices of air and the medium respectively

Given parameters

R = 12 cm

u = $\infty$ (since light incident is parallel to the axis)

n₁ = 1

n₂ = 1.5

Required

<em>focus point of the light that is incident and parallel to the central axis (v)</em>

<em />

Substituting this values into the given formula we will have;

$\dfrac{1.5}{v} - \dfrac{1}{\infty}= \dfrac{1.5-1}{12}\\\\\dfrac{1.5}{v} -0= \dfrac{0.5}{12}\\\\\dfrac{1.5}{v}= \dfrac{0.5}{12}\\\\$

Cross multiply

$1.5*12 = 0.5*v\\ \\18 = 0.5v\\\\v = \frac{18}{0.5}\\ \\v = 36cm$

Hence Light incident parallel to the central axis is focused at a point 36cm from the surface

6 0

3 years ago

What is the acceleration of a car at rest that speeds up to 75m/s over 25 seconds?

Yuki888 [10]

It’s a because I just did it

6 0

3 years ago

Two charged spheres on a frictionless horizontal surface are attached to opposite ends of a string & are in static equilibri

deff fn [24]

Answer:

the red sphere has a charge of 9.899 10⁻⁶ C and

the green sphere 0.101 10⁻⁶ C

Explanation:

For this exercise we will use coulomb's law

F = k q₁ q₂ / r²

where they indicate the value of the force F = 2.5 N, the distance between them r = 0.06 m

they also indicate the value of the total load

q₁ + q₂ = 10 10⁻⁶ C

we substitute the values

2.5 = 9 10⁹ q₁ q₂ / 0.06²

2.5 0.06 2/9 10⁹ = q₁ q₂

1 10⁻¹² = q₁ q₂

10 10⁻⁶= q₁ + q₂

we have two equations with two i unknowns, so the system can be solved.

q₁ = 1 10⁻¹² / q₂

we substitute in the other equation

10 10⁻⁶ = 10⁻¹² / q₂ + q₂

let's solve the equation

10 10⁻⁶ q₂ = 10⁻¹² + q₂²

q₂² - 10⁻⁵ q₂ + 10⁻¹² = 0

q₂ = [10⁻⁵ ± √(10⁻¹⁰ - 4 10⁻¹²)] / 2

q₂ = [10⁻⁵ + - 0.9798 10⁻⁵] / 2 = 10⁻⁵ (1 + - 0.9798) / 2

q₂ = 0.9899 10⁻⁵ C

q₂ = 0.0101 10⁻⁵ C

let's find the charge of the other sphere

q₂ = 0.9899 10⁻⁵ C

q₁ = 10⁻⁵ - q₂

q₁ = 10⁻⁵ - 0.9899 10⁻⁵

q₁ = 0.0101 10⁻⁵ C

therefore the red sphere has a charge of 9.899 10⁻⁶ C and

the green sphere 0.101 10⁻⁶ C

5 0

3 years ago

Can electrons travel in speed of light?

Virty [35]

Yes

Is a pop quiz! :)
:( ;)

6 0

3 years ago