Yes, they are the same. They are equivalent.
Answer:
Percentage mass of copper in the sample = 32%
Explanation:
Equation of the reaction producing Cu(NO₃) is given below:
Cu(s)+ 4HNO₃(aq) ---> Cu(NO₃)(aq) + 2NO₂(g) + 2H₂O(l)
From the equation of reaction, 1 mole of Cu(NO₃) is produced from 1 mole of copper. Therefore, 0.010 moles of Cu(NO₃) will be produced from 0.010 mole of copper.
Molar mass of copper = 64 g/mol
mass of copper = number of moles * molar mass
mass of copper = 0.01 mol * 64 g/mol = 0.64 g
Percentage by mass of copper in the 2.00 g sample = (0.64/2.00) * 100%
Percentage mass of copper in the sample = 32%
As,
Kw = [H+] [OH-]
For water, [H+] = [OH-]
Therefore we can write
Kw = [H+]²
9.311 × 10-14 = [H+]²
[H+] =
3.04 × 10-7 = [OH-]
Ph = - log [H+]
= - log (
3.04 × 10-7)
= 6.52
Thus, Ph = PoH = 6.52
