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elixir [45]
2 years ago
14

Which group is an international organization which United States is involved

Physics
1 answer:
Harlamova29_29 [7]2 years ago
4 0

Answer:

D. The World Bank.

Explanation:

UNDP is an acronym for United Nations Development Programme and it is a global (world) development initiative of the United Nations (UN). The main purpose of the United Nations Development Programme (UNDP) is to provide resources such as loans, grants and training to developing nations in order to improve their technical plans and infrastructural investments. One of the programmes sponsored by the United Nations Development Programme (UNDP) in developing countries around the world is the Sustainable Development Goals (SDGs).

Similarly, The World Bank is an international financial institution that is saddled with the responsibility of providing loans and grants to developing countries just like the United Nations Development Programme (UNDP).

Furthermore, several countries across the world such as Nigeria, Austria, Japan, Germany, United Kingdom, Ghana, Netherlands, Guinea, Brazil, Canada, China, Qatar, Egypt, United States of America, etc.

Hence, the World Bank is an international organization which the United States of America is involved.

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An x-ray beam of wavelength 1.4×10−10m makes an angle of 20° with a set of planes in a crystal(the Bragg angle)causing first ord
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Answer:

Second order line appears at 43.33° Bragg angle.

Explanation:

When there is a scattering of x- rays from the crystal lattice and interference occurs, this is known as Bragg's law.

The Bragg's diffraction equation is :

n\lambda=2d\sin\theta      .....(1)

Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.

Given :

Wavelength, λ = 1.4 x 10⁻¹⁰ m

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Substitute these value in equation (1).

1\times1.4\times10^{-10} =2d\sin20

d = 2.04 x 10⁻¹⁰ m

For second order constructive interference, let the Bragg's angle be θ₁.

Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).

2\times1.4\times10^{-10} =2\times2.04\times10^{-10} \sin\theta_{1}

\sin\theta_{1} =0.68

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A distant planet with a mass of (7.2000x10^26) has a moon with a mass of (5.0000x10^23). The distance between the planet and the
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Answer:

Explanation:

This is a simple gravitational force problem using the equation:

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

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F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2} I'm going to do the math on the top and then on the bottom and divide at the end.

F_g=\frac{2.4012*10^{40}}{3.721*10^{23}} and now when I divide I will express my answer to the correct number of sig dig's:

Fg= 6.45 × 10¹⁶ N

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