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nikdorinn [45]
3 years ago
7

Find the force necessary to start the crate moving, given that the mass of the crate is 32 kg and the coefficient of static fric

tion between the crate and the floor is 0.57. Express your answer using two significant figures.
Physics
1 answer:
fiasKO [112]3 years ago
3 0

Answer:

178.75 N

Explanation:

The force necessary to start moving the crate must be equal to or more than the frictional force (resistive force) acting on the crate but moving in an opposite direction to the frictional force.

So, we find the frictional force, Fr:

Fr = -μmg

Where μ = coefficient of friction

m = mass

g = acceleration due to gravity

The frictional force is negative because it acts against the direction of motion of the crate.

Fr = -0.57 * 32 * 9.8

Fr = - 178.75 N

Hence, the force necessary to move the crate must be at least equal to but opposite in direction to this frictional force.

Therefore, this force is 178.75 N

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What is the change in internal energy of the system (∆U) in a process in which 10 kJ of heat energy is absorbed by the system an
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Answer:

Explanation:

According to first law of thermodynamics:

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∆U = -10 + (+70) = +60 kJ

Thus, the internal energy of the system decreases by 60 kJ.

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3 years ago
A small airplane takes on 302 l of fuel. If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?
ella [17]

To calculate the mass of the fuel, we use the formula

m = V \times  \rho

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Substituting these values in above relation, we get  

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8 0
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two negative charges that are both -3.0 C push each other apart with a force of 19.2 N how far apart are the charges
Hoochie [10]
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
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If we use F=19.2 N and q1=q2=-3.0 C, we can find the value of r, the  distance between the two charges by re-arranging the previous formula:
r= \sqrt{k_e \frac{q_1 q_2}{F} }= \sqrt{ 8.99 \cdot 10^9 N m^2 C^{-2} \frac{(-3.0C)^2}{19.2 N} } =6.49 \cdot 10^4 m=64.9 km
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3 years ago
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