Find the force necessary to start the crate moving, given that the mass of the crate is 32 kg and the coefficient of static fric
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Answer:
The correct solution is "37.5 km".
Explanation:
Given:
Distance between the trains,
d = 75 km
Speed of each train,
= 15 km/h
The relative speed will be:
=
=
The speed of the bird,
V = 15 km/h
Now,
The time taken to meet will be:
hence,
The distance travelled by the bird in 2.5 h will be:
⇒
Here we have a circular motion. In that type of motion two new forces appear: centrifugal and centripetal. Centrifugal force tries to move object away frome the center of rotation. Centripetal force is the reason why object moves in a circle.
According to Newton's first law, in order for water not to spill out total force acting on water must be equal to zero. Forces acting on the water are gravitational and centrifugal.
![0= F_{g} + F_{c} \\ - [tex]F_{g} = F_{c} \\ m*g= \frac{m* v^{2} }{r} \\ g= \frac{ v^{2} }{r} \\ v^{2} =g*r \\ v= \sqrt{g*r} \\ v= \sqrt{9.81*0.95} \\ v= \sqrt{9.3195} \\ v=3.1 m/s](https://tex.z-dn.net/?f=0%3D%20F_%7Bg%7D%20%2B%20F_%7Bc%7D%20%20%5C%5C%20-%20%5Btex%5DF_%7Bg%7D%20%3D%20F_%7Bc%7D%20%5C%5C%20m%2Ag%3D%20%5Cfrac%7Bm%2A%20v%5E%7B2%7D%20%7D%7Br%7D%20%20%5C%5C%20g%3D%20%5Cfrac%7B%20v%5E%7B2%7D%20%7D%7Br%7D%20%5C%5C%20%20v%5E%7B2%7D%20%3Dg%2Ar%20%5C%5C%20%20v%3D%20%5Csqrt%7Bg%2Ar%7D%20%20%5C%5C%20v%3D%20%5Csqrt%7B9.81%2A0.95%7D%20%20%5C%5C%20v%3D%20%5Csqrt%7B9.3195%7D%20%20%5C%5C%20v%3D3.1%20m%2Fs)
[/tex]
Forces have opposite signs as they act in opposite directions. But their value is the same so we can ignore signs:
According to Newton's first law, in order for water not to spill out total force acting on water must be equal to zero. Forces acting on the water are gravitational and centrifugal.
Forces have opposite signs as they act in opposite directions. But their value is the same so we can ignore signs: