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Juliette [100K]
3 years ago
7

Trans-2-butene does not exhibit a signal in the double-bond region of the spectrum (1600–1850 cm−1); however, ir spectroscopy is

still helpful in identifying the presence of the double bond. identify the other signal that would indicate the presence of a c=c bond.
Chemistry
1 answer:
Elza [17]3 years ago
3 0
However <em>trans</em>-2-Butene does not give a characteristic peak in 1620-1680 cm⁻¹ region but still the presence of carbon double bond carbon can be detected by detecting following peaks in IR Spectrum.

1)  3010-3100 cm⁻¹:
                               As in trans-2-Butene a hydrogen atoms ate attached to sp² hybridized carbon, therefore the stretching of =C-H (C-H) bond will give a peak of medium intensity in the range of 3010-3100 cm⁻¹.

2)  675-1000 cm⁻¹:
                             Another peak which is given by the bending of =C-H (C-H) bond with strong intensity will appear in the range of 675-1000 cm⁻¹.
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Step 4: Solve the equation.<br> KE = 27.5 kg x 4 m²/s2<br> =
harkovskaia [24]
Kinetic energy is 1/2m*v^2
They already halved the mass for you and they already squared the velocity for you. I’m unsure why you’re even asking this question. It’s simple multiplication at this point.
(27.5kg)*(4m^2/s^2) = 110 Jules
4 0
3 years ago
At which temperature do the molecules of an ideal gas have 3 times the kinetic energy they have at 32of?
algol [13]

Answer:

  • 820 K

Explanation:

As per Boltzman equation, <em>kinetic energy (KE)</em> is in direct relation to the <em>temperature</em>, measured in absolute scale Kelvin.

  • KE α T.

Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>

So, you must just convert the given temperature, 32°F, to kelvin scale.

You can do that in two stages.

  • First, convert 32°F to °C. Since, 32°F is the freezing temperature of water, you may remember that is 0°C. You can also use the conversion formula: T (°C) = [T (°F) - 32] / 1.80

  • Second, convert 0°C to kelvin:

         T (K) = T(°C) + 273.15 K= 273.15 K

Then, <u>3 times</u> gives you: 3 × 273.15 K = 819.45 K

Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.

7 0
3 years ago
You
Igoryamba

Answer:

The arm that was not sprayed with anything

Explanation:

The control group would be <u>the arm that was not sprayed with anything</u>.

<em>The control group during an experiment is a group that forms the baseline for comparison in other to determine the effects of a treatment. The control group does not include the variable that is being tested and as such, it provides the benchmark to measure the effects of the tested variable on the other group - the experimental group. In this case, the experimental group would be the arm that was sprayed with the repellent.</em>

8 0
3 years ago
Part b select the ester that is formed when propanoic acid reacts with isopropyl alcohol in the presence of heat and an acid cat
Otrada [13]
<span>The ester that is formed by combining propanioc acid with isopropyl alcohol, using heat and an acid catalyst is isopropyl propanoate.</span>
7 0
3 years ago
Temperature in degrees Fahrenheit can be converted to Celsius by first subtracting 32, then dividing by 1.8. What is the Celsius
kap26 [50]

Answer:

31.1°C

Explanation:

Given parameters:

  Temperature = 88°F

The formula of the to convert is:

         T°F = T°C - 32  / 1.8  = \frac{TC - 32}{1.8}

Now input the parameters and solve;

       T°F =\frac{ 88  -32}{1.8}

      T°F = 31.1°C

7 0
3 years ago
Read 2 more answers
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