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eimsori [14]
4 years ago
15

An object is given an initial velocity. What will happen to the object if no other forces act on it?

Physics
1 answer:
Phoenix [80]4 years ago
6 0

Answer:

The object will travel at a constant rate in along a straight line.

Explanation:

In the given situation, it is mentioned that there is no external force acting on the given object. Thus, it will retain its initial velocity along a straight path.

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The plates of a parallel-plate capacitor are maintained with a constant voltage by a battery as they are pushed together, withou
Dominik [7]

Answer:

The amount of charge on the plates increases during this process

Explanation:

In order to maintain a constant voltage across the plates, pushing the plates closer will increase the charge on the plate

7 0
3 years ago
In a redox reaction, what happens to a substance's charge when it is reduced?
algol [13]

A) it gets more negative

B) it becomes neutral

C) it gets more positive

D) it becomes reactive





(C) ;)
8 0
3 years ago
As a basketball player starts to jump for a rebound, he begins to move upward faster and faster until he leaves the floor. Durin
Anastasy [175]

Answer:

The force of the floor on his shoes is bigger than his weight.

Explanation:

From Newton's third law of motion which states that to every action there is an equal an opposite reaction, we can say that the ground exerts additional force on the basketball player, thereby overcoming his weight and pushing him off the ground.

So, when the basketball player jumps, his muscles contract or extend appropriately which in turn creates an additional force on the ground. Hence, the force of the floor on his shoes is bigger than his weight.

5 0
3 years ago
Is the energy of a wave is calculated by squaring the frequency of the wave?
Misha Larkins [42]
Nope.
Energy is directly proportional to frequency. and when you calculate energy, you multiply frequency with a constant number called "Planck's Constant"

E = hf

Hope this helps!
5 0
3 years ago
A skier starts from rest at the top of a 45.0-m-high hill, skis down a 30° incline into a valley, and continues up a 40.0-m-high
Wewaii [24]

1) The speed of the skier at the bottom of the valley is 29.7 m/s

2) The speed of the skier at the top of the second hill is 9.9 m/s

3) No, the angle of the hills does not affect the result

Explanation:

1)

We can solve this problem by using the law of conservation of energy. In fact, in absence of friction, the total mechanical energy of the skier is conserved:

E=U+K

where

E is the total mechanical energy

U is the gravitational potential energy

K is the kinetic energy

At the top of the hill, K = 0 since the skier is at rest, so all its energy is potential energy:

E=U=mgh (1)

where

m is the mass of the skier

g=9.8 m/s^2 is the acceleration of gravity

h = 45.0 m is the height of the hill

As the skier descends the hill, the potential energy is converted into kinetic energy. At the bottom, all the mechanical energy has been converted into kinetic energy:

E=K=\frac{1}{2}mv^2

where

v is the speed of the skier at the bottom of the hill

Since the total energy is conserved,

U=K\\mgh=\frac{1}{2}mv^2

And so we find

v=\sqrt{2gh}=\sqrt{2(9.8)(45)}=29.7 m/s

2)

The top of the next hill is located at a height of

h' = 40.0 m

So the total mechanical energy at the top of the second hill is

E=U'+K' = mgh'+\frac{1}{2}mv'^2

where v' is the speed at the top of the second hill.

Since the total mechanical energy must be conserved, we can equate this energy to mechanical energy at the beginning (eq. 1), so we have

mgh = mgh' + \frac{1}{2}mv'^2

and we can now solve for v':

v=\sqrt{2g(h-h')}=\sqrt{2(9.8)(45-40)}=9.9 m/s

3)

As we saw from the previous equations, the angles of the hill does not enter at all the calculations, so it does not affect the value of the speed of the skier.

The reason for this is that the gravitational potential energy of the skier depends only on the height of the hill, h and h', and not from the length of the path along the hill (and so, not on the angle of the hill), and therefore the angle does not enter the calculation.

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

4 0
3 years ago
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