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3 years ago

Not a question, but I need help on the last two questions I posted, preferably no links, please...

Physics

2 answers:

Andrei [34K]3 years ago

7 0

Answer:

ok...

Explanation:

Vadim26 [7]3 years ago

5 0

Answer:

ive gotten links for answers that really looked like a virus

Explanation:

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an airplane flies at a speed of 100 m/s and starts to accelerate constantly at a rate of 50 m/s2. how fast is the plane flying a

mart [117]

Answer:

331.7m/s

Explanation:

Given parameters:

Initial velocity = 100m/s

Acceleration = 50m/s²

Distance = 1km = 1000m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we have to apply the right motion equation shown below;

v² = u² + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

Now insert the parameters and solve;

v² = 100² + (2 x 50 x 1000)

v² = 110000

v = √110000 = 331.7m/s

4 0

2 years ago

The auto in the sketch moves forward as the brakes are applied. A bystander says that during the interval of braking, the auto's

Ivan

Answer:

The statement is true: velocity and acceleration have opposite directions in the interval of braking.

Explanation:

Let's say we have a velocity $v>0$ .

The acceleration $a$ is the rate of change of the velocity $v$ . This means that if $v$ is <em>increasing during</em> time, then $a$ must be positive. But if $v$ is <em>decreasing over</em> time, then $a$ will be negative (even though the velocity is positive).

Mathematically:

$a=\frac{dv}{dt}$

$v$ decreases ⇒ $\frac{dv}{dt}$

⇒ $a$ .

Example:

$v(t)=e^{-t}>0 \\\\\frac{dv}{dt}=-te^{-t}$

3 0

3 years ago

An airplane travels 975 miles south from one airport to another at an average speed of 250 mph (miles per hour). How much time w

Maru [420]

Answer:

3.9 hours

Explanation:

7 0

2 years ago

Principle of quantization of charge

Musya8 [376]

Charge quantization is the principle that the charge of any object is an integer multiple of the elementary charge. Thus, an object's charge can be exactly 0 e, or exactly 1 e, −1 e, 2 e, etc., but not, say, 12 e, or −3.8 e, etc.

3 0

3 years ago

Read 2 more answers

As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p

Irina-Kira [14]

Answer:

The magnitude of each force is 2.45 x 10⁻¹⁶ N

Explanation:

The charge of proton, +q = 1.603 x 10⁻¹⁹ C

The charge of electron, -q = 1.603 x 10⁻¹⁹ C

Distance between the two charges, r = 971 nm = 971 x 10⁻⁹ m

Apply Coulomb's law;

$F = \frac{kq_1q_2}{r^2}$

where;

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

q₁ and q₂ are the charges of proton and electron respectively

F is the magnitude of force between them

Substitute in the given values and solve for F

$F = \frac{(8.99*10^9)(1.603*10^{-19})^2}{(971*10^{-9})^2} \\\\F = 2.45*10^{-16} \ N$

Therefore, the magnitude of each force is 2.45 x 10⁻¹⁶ N

4 0

2 years ago