Answer:
0.25A
1.0A
2.5A
Explanation:
this is only for the calculated current column on edge
12 MPH
I DIDNT do the math my brother did hes in colledge so good lucks guys
Answer:
Explanation:
Answer: Let ke = 1/2 IW^2 = 1/2 kMr^2 W^2 be Earth's rotational KE. W = 2pi/24 radians per hour rotation speed and k = 2/5 for a solid sphere M is Earth mass, r = 6.4E6 m.
Then ke = 1/2 2/5 6E24 (6.4E6)^2 (2pi/(24*3600))^2 = ? Joules. You can do the math, note W is converted to radians per second for unit consistency.
Let KE = 1/2 KMR^2 w^2 be Earth's orbital KE. w = 2pi/(365*24) radians per hour K = 1 for a point mass. Note I used 365 days, a more precise number is 365.25 days per year, which is why we have Leap Years.
Find KE/ke = 1/2 KMR^2 w^2//1/2 kMr^2 W^2 = (K/k)(w/W)^2 (R/r)^2 = (5/2) (365)^2 (1.5E11/6.4E6)^2 = 7.81E9 ANS
Answer: The kinetic energy in physics can be defined as the energy possessed by the body when it is in motion relatively to the other bodies. This energy depends on the mass of the body and the square of the velocity. Its measurable unit is in Joules.
Answer and Explanation:
Given data:
The electric field is
E
=
1000
N
/
C
The initial kinetic energy of the ejected electrons is
k
=
3
e
V
=
(
3
×
1.6
×
10
−
19
)
J
The expression for the conservation of energy of the electrons is given by
k
=
U
p
k
=
e
V
Here
U
p
=
e
V
is the potential energy of the electron
Here
V
=
E
d
is the electric potential in electric field
Here
e
=
1.6
×
10
−
19
C
is the charge of the electon
Substituting the values in the above equation as,
k
=
q
V
k
=
e
(
E
d
)
(
3
×
1.6
×
10
−
19
J
)
=
(
1.6
×
10
−
19
C
)
(
1000
N
/
C
)
×
d
d
=
0.003
m
d
=
3
m
m
Explanation:
