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NeX [460]
3 years ago
7

Not a question, but I need help on the last two questions I posted, preferably no links, please...

Physics
2 answers:
Andrei [34K]3 years ago
7 0

Answer:

ok...

Explanation:

Vadim26 [7]3 years ago
5 0

Answer:

ive gotten links for answers that really looked like a virus

Explanation:

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A particle's velocity is described by the function vx = kt 2 m/s, where k is a constant and t is in s. The particle's position a
vodomira [7]

Answer:

The value of the constant k is 2

Explanation:

We have the equation of the velocity v_{x} = kt² , where k

is constant and t is the time in second

The particle's position at t_{0} = 0 is x_{0} = -9 m

The particle's position at t_{1} = 3 s is x_{1} = 9 m

We need to find the value of the constant k

The relation between the velocity and the displacement in a particular

time is x = \int\ {v_{x} } \, dt

Remember in integration we add power by 1 and divide the expression

by the new power

→ x = \int\ {kt^{2} } \, dt=\frac{1}{3}kt^{3}+c

c is the constant of integration to find it substitute the initial value of x

and t in the equation of x

→ t_{0} = 0 , x_{0} = -9 m

→ -9 = \frac{1}{3} k (0)³ + c

→ -9 = c

Substitute the value of c in the equation of x

→ x = \frac{1}{3} k t³ - 9

To find k substitute the values of  t_{1} = 3 s , x_{1} = 9 m

→ 9 = \frac{1}{3} k (3)³ - 9

→ 9 = \frac{1}{3} (27) k - 9

→ 9 = 9 k - 9

Add 9 to both sides

→ 18 = 9 k

Divide both sides by 9

→ k = 2

<em>The value of the constant k is 2</em>

5 0
4 years ago
1. (15 points) Small cart is rolling down an inclined track and accelerating. It fires a ball straight out of the cannon as it m
Elena L [17]

Answer:

Explanation:

This problem can be solved with the conservation of the momentum.

If the ball is fired upward, the momentum before and after the ball is fired must conserve. Hence, the speed of the ball is the same that the speed of the car just in the moment in wich the ball is fired.

Hence, the result depends of the acceleration of the car. If the change in the speed is higher than the speed of the ball, it is probably that the ball will be behind the car or it will come back to the car.

If the ball is fired forward, and if the change in the speed of the car is not enogh, the ball will be in front of the car.

HOPE THIS HELPS!!

5 0
3 years ago
A neutral atom of tin (Z = 50) has 69 neutrons. (a) How many protons does it have? (b) What is its mass number?
Olenka [21]

Answer:

Protons = 50

Mass number = 119

Explanation:

A neutral of tin, Sn, has a Z value of 50 and neutrons are 69.

Z is the atomic number. The atomic number is equal to number of protons or number of electrons in an atom that is neutral i.e:

Z = PROTONS = ELECTRONS

So the number of protons = 50 since Z is 50

>>>>>>>>>>>>>>>¦

The bulk of the mass of an atom is concentrated in the nucleus. To calculate mass number, we simply sum all the elementary particles in the nucleus i.e protons and neutrons. These particles are called the nucleons.

Mass number (A) = P + N

= 50 + 69

= 119

3 0
3 years ago
T/F all compounds are molecules but NOT all molecules are compounds.
Solnce55 [7]
True because molecules don't have to be compounds but compounds have to be molecules
7 0
3 years ago
A bodybuilder deadlifts a 215 kg weight to a height of 0.90 m above the ground. If he deadlifts this weight 10 times in a span o
wariber [46]

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

<h3>What is power?</h3>

In physics, power (P) is the work (W) done over a period of time.

  • Step 1. Calculate the work done by the bodybuilder each time.

The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.

W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N

  • Step 2. Calculate the work done by the bodybuilder over 10 times.

W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N

  • Step 3. Calculate the power exerted by the bodybuilder.

The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.

P = 1.9 × 10⁴ N/45 s = 421 W

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

Learn more about power here: brainly.com/question/911620

#SPJ1

4 0
2 years ago
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