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Ilya [14]
3 years ago
8

If the density of copper (Cu) is 8.96 g/cm3 and that of zinc (Zn) is 7.13 g/cm3. Calculate and compare the volume of a pre-1982

penny to that of a post-1982 penny? Give one reason to support your answer
Chemistry
1 answer:
AveGali [126]3 years ago
8 0

Answer with Explanation:

Density of copper(Cu)=\rho_{Cu}=8.96g/cm^3

Density of zinc(Zn)=\rho_{Zn}=7.13 g/cm^3

Atomic mass of copper=63.546 g

Atomic mass of zinc=65.38 g

We know that

Volume=\frac{mass}{\rho}

Using the formula

Volume of copper=\frac{63.546}{8.96}=7.09 cm^3

Volume of zinc=\frac{65.38}{7.13}=9.17 cm^3

Volume is inversely proportional to  the density.

Pre -1982 penny made by copper and post-1982 penny made by zinc.

Therefore, volume of post-1982 penny is greater than the volume of pre-1982 penny because density of zinc is less than the density of copper.

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Explanation:

Let's first take account of what we have and convert them into the correct units.

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Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be

n=\frac{PV}{RT}, where R (constant)= 0.082 L atm mol-1 K-1

Let's plug in what we know.

n=\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}

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Let's look back at MM= \frac{m}{n} and plug in what we know.

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MM= 49.2 g/mol

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