Answer:
6010.457N
Explanation:
Centripetal acceleration = a= V²/R
At a radius of 3.6m and velocity of 16.12m/s,
Acceleration is
a = 16.12²/ 3.6 = 72.182 m/s²
Force = Mass (m) * Acceleration (a)
36 = m * 72.182
m = 36/72.182
At breaking point
Radius = 0.468 m and Velocity = 75.1 m/s
a = V²/R = 75.1²/0.468
a = 12051.3 m/s
F = Mass(m) * Acceleration (a)
F = m * 12051.3
m = F/ 12051.3
Settings the ratio of mass equal
m = m
=> 36/72.182 = F/12051.3
F = 12051.3 * 36/72.182
F = 6010.457N
Answer:
(a): I = 4.6875 A
(b): P = 562.5 W
(c): P mech = 492.1875 W
Explanation:
Data Given:
V= 120 V
E= 105 V
R= 3.2 Ω
To find:
(a): I = ?
As we know that in a DC series motor the equation to be used will be:
V = Ε + (I) (R)
120 V = 105 V + ( I ) (3.2 Ω),
I= 15/3.2
I= 4.6875 A ans
Now moving towards Power delivered i.e.
(b): P del :
P del = V X I = (120 V) (4.6875 A) = 562.5 W. ans
c) P mech = ?
The mechanical power output is the electrical power input minus the rate of dissipation of energy in the motor’s resistance (assuming that there are no other power losses):
The power P dissipated in the resistance r is
P dsptd = I²r = (4.6875 A)² X(3.2 Ω) = 70.3125 W
P mech = P del - P dsptd
P mech = 562.5 W — 70.3125 W = 492.1875 W Ans
Hope it is clear
Thank you kind person
*hands you a whole gallon of ketchup :)))