All categories

2 years ago

Many of the rocks of the canyon wall appear as horizontal bands. What do the bands indicate about the way the rocks formed?

1 answer:

4 0

Given what we know, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

<h3>What do these bands tell us about the canyon?</h3>

The bands are the result of sediments being deposited as the canyon was being formed. These sediments are deposited by the running water that carves the canyon. This results in horizontal bands that can tell us much about the history of the canyon as well as the river that formed it.

Therefore, we can confirm that the bands indicate that the canyon was carved due to erosion caused by moving water.

To learn more about erosion visit:

brainly.com/question/2635044?referrer=searchResults

You might be interested in

A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is

Rudiy27

The tension in the cable is equal to 323.5 N.

<h3>What is the tension in the cable?</h3>

The tension, T in the cable is determined by taking moments about the pivot marked X.

The angles of the boom and the cable with the horizontal are first calculated.

Angle of the boom with horizontal, θ = tan⁻¹(5/10) = 26.56°

The angle of cable with horizontal, B = tan⁻¹(4/10) = 21.80

Taking moments about the pivot:

175.5 * cos 26.56 + 94.7 * cos 26.56 * 0.5 = T (sin(26.56 + 21.80) * 1

Tension = 241.68/0.747

Tension = 323.5 N

In conclusion, the tension in the cable helps to suspend the crate.

Learn more about tension at: brainly.com/question/24994188

#SPJ1

6 0

2 years ago

Please help me out

Licemer1 [7]

Answer:

Explanation:

Because you would need to be able to handle the weight to move it.

3 0

4 years ago

Scientist who discovered that the nucleus contains neutrons in addition to protons.

ZanzabumX [31]

Answer: James Chadwick

5 0

3 years ago

The top of a tower much like the leaning bell tower at Pisa, Italy, moves toward the south at an average rate of 1.4 mm/y. The t

Gemiola [76]

Answer:

$\omega=7.16*10^{-13}\frac{rad}{s}$

Explanation:

The angular speed is given by:

$\omega=\frac{v}{r}$

Here v is the linear speed and r is the radius of the circular motion. The height of the tower is equal to the radius of the circular motion of the top of the tower, since is rotating about its base. We need to convert the given linear speed to $\frac{m}{s}$ :

$1.4\frac{mm}{y}*\frac{10^{-3}m}{1mm}*\frac{1y}{3.154*10^7s}=4.44*10^{-11}\frac{m}{s}$

Now, we calculate the angular speed:

$\omega=\frac{4.44*10^{-11}\frac{m}{s}}{62m}\\\omega=7.16*10^{-13}\frac{rad}{s}$

8 0

4 years ago

A 4500 kg car accelerates from rest to 45.0

Llana [10]

The car undergoes an acceleration a such that

(45.0 km/h)² - 0² = 2 a (90 m)

90 m = 0.09 km, so

(45.0 km/h)² - 0² = 2 a (0.09 km)

Solve for a :

a = (45.0 km/h)² / (2 (0.09 km)) = 11,250 km/h²

Ignoring friction, the net force acting on the car points in the direction of its movement (it's also pulled down by gravity, but the ground pushes back up). Newton's second law then says that the net force F is equal to the mass m times the acceleration a, so that

F = (4500 kg) (11,250 km/h²)

Recall that Newtons (N) are measured as

1 N = 1 kg • m/s²

so we should convert everything accordingly:

11,250 km/h² = (11,250 km/h²) (1000 m/km) (1/3600 h/s)² ≈ 0.868 m/s²

Then the force is

F = (4500 kg) (0.868 m/s²) = 3906.25 N ≈ 3900 N

8 0

4 years ago