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dlinn [17]
3 years ago
6

A DOHC V-6 has how many camshafts?

Engineering
1 answer:
viktelen [127]3 years ago
4 0

Answer:

two camshafts

Explanation:

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1 A power transmission includes a belt drive, a chain drive and a gear drive. Which of the following is the best arrangement bet
Setler79 [48]

Answer:d

Explanation:

(d) chain drive belt drive gear drive

3 0
3 years ago
What should always be done before beginning any diagnosis?
vladimir2022 [97]

Answer:

c

Explanation:

if someone is wrong that they can help with

4 0
2 years ago
The domain of discourse is the members of a chess club. The predicate B(x, y) means that person x has beaten person y at some po
satela [25.4K]

Answer:A. No one has ever beat Nancy.

Explanation:

The dormain of discourse in a simple language is the set of entities upon which our discussions are based when discussing about something.

The dormain of discourse is also known simply as universe, can also be said to be a set of entities o

upon which certain variables of interest in some formal treatment may range.

The dormain of discourse is generally attributed to Augustus De Morgan, it was also extensively used by George Boole in his Laws of Thought.

THE LOGICAL UNDERSTANDING OF THE THE QUESTION IS THAT NO ONE HAS EVER BEAT NANCY.

8 0
3 years ago
Which material has the highest cp value?
Nataly [62]

Answer: B. Water

Explanation:

6 0
2 years ago
A cylindrical brass rod has a length of 5.00cm extending from a holder and a diameter of 4.50mm. Its Young's modulus is 98.0GPa.
Galina-37 [17]

Answer:

elongation of the brass rod is 0.01956 mm

Explanation:

given data

length = 5 cm = 50 mm

diameter = 4.50 mm

Young's modulus = 98.0 GPa

load = 610 N

to find out

what will be the elongation of the brass rod in mm

solution

we know here change in length formula that is express as

δ = \frac{PL}{AE}    ................1

here δ is change in length and P is applied load  and A id cross section area and E is Young's modulus and L is length

so all value in equation 1

δ = \frac{PL}{AE}  

δ = \frac{610*50}{\frac{\pi}{4} * 4.50^2 * 98*10^3}  

δ = 0.01956 mm

so elongation of the brass rod is 0.01956 mm

7 0
3 years ago
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