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3 years ago

12

The critical resolved shear stress for iron is 27 MPa (4000 psi). Determine the maximum possible yield strength for a single cry

stal of Fe pulled in tension.

1 answer:

jasenka [17]3 years ago

7 0

Answer:

Answer is mentioned below.

Explanation:

Answer: Calculation of maximum yield strength for a single crystal of Fe pulled in tension is shown in the image attached .

value of max. Yield strength= 54MPa

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3 years ago

The velocity of a particle which moves along the s-axis is given by v = 2-4t+5t^(3/2), where t is in seconds and v is in meters

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b) V = 26 m/s

c) a = 11 m/s²

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The velocity(V) = 2 - 4t + 5t^3/2 where t is in seconds and V is in m/s

a) To get the position, we have to integrate the velocity with respect to time.

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c = 2

Therefore

$s=(2t-2t^{2} +\frac{10}{5}t^{\frac{5}{2} }+2)m$

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$s=2(4)-2(4)^{2} +2(4)^{\frac{5}{2} }+2$

$s=8-32+64+2$

s = 42 m

At t= 4s, the position s = 42m

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$V=(2-4t+5t^{\frac{3}{2} })m/s$

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$V=2-4(4)+5(4)^{\frac{3}{2} }$

V = 2 - 16 + 40 = 26 m/s

The velocity(V)at t = 4 s is 26 m/s

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$a=\frac{d}{dt}(2-4t+5t^{ \frac{3}{2}})$

Differentiating with respect to t,

$a=-4+\frac{15}{2}t^{\frac{1}{2} }$

$a=(-4+\frac{15}{2}t^{\frac{1}{2} })m/s^{2}$

At t = 4 s,

$a=-4+\frac{15}{2}(4)^{\frac{1}{2} }$

$a=-4+15$

a = 11 m/s²

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