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weqwewe [10]
3 years ago
12

The critical resolved shear stress for iron is 27 MPa (4000 psi). Determine the maximum possible yield strength for a single cry

stal of Fe pulled in tension.

Engineering
1 answer:
jasenka [17]3 years ago
7 0

Answer:

Answer is mentioned below.

Explanation:

Answer: Calculation of maximum yield strength for a single crystal of Fe pulled in tension is shown in the image attached .

value of max. Yield strength= 54MPa

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Explain the concept of degrees of freedom in terms of physics and mechanics.
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Explanation:

Step1

Degree of freedom is the number of independent variable which is required to define motion of the system. Degree of freedom is the number of possible motion of the system. Motion can be sliding or rotate. So, there are maximum 6 possible motions of the system, 3 of rotation and 3 of translation. There are 6 maximum possible degrees of freedoms.

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The velocity of a particle which moves along the s-axis is given by v = 2-4t+5t^(3/2), where t is in seconds and v is in meters
Brut [27]

Answer:

a) s = 42 m

b) V = 26 m/s

c) a = 11 m/s²

Explanation:

The velocity(V) = 2 - 4t + 5t^3/2 where t is in seconds and V is in m/s

a) To get the position, we have to integrate the velocity with respect to time.

We get the position(s) from the equation:

V=\frac{ds}{dt}

ds=Vdt

Integrating both sides,

s=\int\ {V} \, dt

s=\int\ {(2-4t+5t^{\frac{3}{2} })  \, dt

Integrating, we get

s=(2t-2t^{2} +2t^{\frac{5}{2} }+c)m

But at t=0, s(0) = 2 m

Therefore,

s(0)=2(0)-2(0)^{2} +2(0)^{\frac{5}{2} }+c  

2=0+0+0+c

c = 2

Therefore

s=(2t-2t^{2} +\frac{10}{5}t^{\frac{5}{2} }+2)m

When t = 4,

s=2(4)-2(4)^{2} +2(4)^{\frac{5}{2} }+2

s=8-32+64+2

s = 42 m

At t= 4s, the position s = 42m

b) The velocity equation is given by:

V=(2-4t+5t^{\frac{3}{2} })m/s

At t = 4,

V=2-4(4)+5(4)^{\frac{3}{2} }

V = 2 - 16 + 40 = 26 m/s

The velocity(V)at t = 4 s is 26 m/s

c) The acceleration(a) is given by:

a=\frac{dv}{dt}

a=\frac{d}{dt}(2-4t+5t^{ \frac{3}{2}})

Differentiating with respect to t,

a=-4+\frac{15}{2}t^{\frac{1}{2} }

a=(-4+\frac{15}{2}t^{\frac{1}{2} })m/s^{2}

At t = 4 s,

a=-4+\frac{15}{2}(4)^{\frac{1}{2} }

a=-4+15

a = 11 m/s²

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2 years ago
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