Once a design is final engineer needs a plan for product

Write a program to display a histogram based on a number entered by the user. A histogram is a graphical representation of a num

lilavasa [31]

Answer:

// CPP program to make histogram of an array

#include <bits/stdc++.h>

using namespace std;

void printHistogram(int arr[], int n)

{

int maxEle = *max_element(arr, arr + n);

for (int i = maxEle; i >= 0; i--) {

cout.width(2);

cout << right << i << " | ";

for (int j = 0; j < n; j++) {

// if array of element is greater

// then array it print x

if (arr[j] >= i)

cout << " x ";

// else print blank spaces

else

cout << " ";

}

cout << "\n";

}

// print last line denoted by ----

for (int i = 0; i < n + 3; i++)

cout << "---";

cout << "\n";

cout << " ";

for (int i = 0; i < n; i++) {

cout.width(2); // width for a number

cout << right << arr[i] << " ";

}

// Driver code

int main()

{

int arr[10] = { 10, 9, 12, 4, 5, 2,

8, 5, 3, 1 };

int n = sizeof(arr) / sizeof(arr[0]);

printHistogram(arr, n);

return 0;

}

Explanation:

The idea is to print the given histogram row by row. For every element, we check if it is greater than or equal to current row. If yes, put a ‘x’ for that element. Else we put a space.

6 0

3 years ago

Ginger feels like she is very qualified for a Revenue job. Which qualification does Ginger most likely have?

deff fn [24]

Explanation:

The qualifications Ginger most likely have to become very qualified for a Revenue job are integrity, ability to analyze tax forms, and good math skills

Revenue is defined as the amount of money that a company actually receives during a specific period, including discounts and deductions for returned merchandise. This transaction involves money and sometimes large amount of money. Thus, integrity is greatly needed.

Revenue job examples are Revenue Accountant, Revenue Analyst, Revenue Manager.

5 0

3 years ago

Read 2 more answers

I took my dog for a walk, but he wants to go again.

Talja [164]

He probably just like the cool weather or being outside lol

7 0

3 years ago

Heat is applied to a rigid tank containing water initially at 200C, with a quality of 0.25, until the pressure reaches 8 MPa. De

creativ13 [48]

Answer:1747.53KJ/kg

Explanation:

Given data

Initial Temprature $\left ( T_i\right )=200^{\circ}$

Quality $\left ( \chi\right )=0.25$

Final pressure $\left ( P_2\right )=8MPa$

Given tank is rigid therefore specific Volume remains same

now calculating properties at $200^{\circ}$

$\nu _f=0.001156m^3/kg$

$\nu {fg}=0.126434m^3/kg$

$h_f=852.26KJ/kg$

$h_{fg}=1939.8KJ/kg$

Now Specific volume of steam at $200^{\circ}$

$\nu _1=\nu _f+\chi \times \nu {fg}$

$\nu _1=0.001156+0.25\times 0.126434$

$\nu _1=0.03276m^3/kg$

$h_1=h_f+\chi \times h_{fg}$

$h_1=852.26+0.25\times 1939.8$

$h_1=1337.21 KJ/kg$

Now $\nu_1=\nu_2$

$0.03276=\nu_2$

At 8 MPa and $\nu =0.03276m^3/kg$

$\nu _g=0.02356$

Since $\nu _2\ is\ greater\ than \nu _g$

therefore final state of steam is superheated at $T=381^{\circ}$

at this state $h_2=3084.74 KJ/kg$ (obtained from steam table)

Therefore heat added

$Q=h_2-h_1=3084.74-1337.21=1747.53 KJ/kg$

3 0

3 years ago

Give the approximate temperature at which creep deformation becomes an important consideration for each of the following metals:

IrinaVladis [17]

Answer:

The creep temperature for different materials is as follows.

A. Nickel :- $T_{c}$ = 690.4 K

B. Copper :- $T_{c}$ = 542.8 K

C. Iron :- $T_{c}$ = 723.6 K

D. Tungsten :- $T_{c}$ = 1469.2 K

E. Lead :- $T_{c}$ = 240.2 K

F. Aluminium :- $T_{c}$ = 373.2 K

Explanation:

Creep is the slow plastic deformation occur at high elevated temperature.

The approximate temperature for different metals is as follows at which creep becomes considerable.

A. Nickel :- The relation between melting temperature & creep temperature is given by the formula.

$T_{c} = 0.4 T_{m}$

The melting temperature of nickel = 1726 K

Creep temperature $T_{c}$ = 0.4 × 1726

$T_{c}$ = 690.4 K

B. Copper :- The relation between melting temperature & creep temperature for copper is given by the formula.

$T_{c} = 0.4 T_{m}$

The melting temperature of copper = 1357 K

Creep temperature $T_{c}$ = 0.4 × 1357

$T_{c}$ = 542.8 K

C. Iron :- The relation between melting temperature & creep temperature for iron is given by the formula

$T_{c} = 0.4 T_{m}$

The melting temperature of iron = 1809 K

Creep temperature $T_{c}$ = 0.4 × 1809

$T_{c}$ = 723.6 K

D. Tungsten :- The relation between melting temperature & creep temperature for tungsten is given by the formula

$T_{c} = 0.4 T_{m}$

The melting temperature of iron = 3673 K

Creep temperature $T_{c}$ = 0.4 × 3673

$T_{c}$ = 1469.2 K

E. Lead :-The relation between melting temperature & creep temperature for lead is given by the formula

$T_{c} = 0.4 T_{m}$

The melting temperature of lead = 600.5 K

Creep temperature $T_{c}$ = 0.4 × 600.5

$T_{c}$ = 240.2 K

F. Aluminium :- The relation between melting temperature & creep temperature for aluminium is given by the formula

$T_{c} = 0.4 T_{m}$

The melting temperature of lead = 933 K

Creep temperature $T_{c}$ = 0.4 × 933

$T_{c}$ = 373.2 K

8 0

3 years ago