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DochEvi [55]
3 years ago
9

¿Podría predecir con antelación si una disolución acuosa será buena conductora de la corriente eléctrica, sabiendo cuál es el so

luto disuelto y la concentración a la que se encuentra?
Chemistry
1 answer:
Ne4ueva [31]3 years ago
3 0

Answer:

Si.

Explicación:

Sí, podemos predecir si una solución acuosa será un buen conductor de corriente eléctrica si conocemos el soluto que se disuelve en ese líquido y su concentración o cantidad. Hay algunas sustancias que se ionizan cuando se agregan en un líquido como el agua. Debido a esta ionización, será un buen conductor de electricidad. Por ejemplo, la adición de una gran cantidad de cloruro de sodio en agua ioniza y hace que el agua sea un buen medio conductor de electricidad.

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The number of protons + number of neutrons is<br> equal to the
max2010maxim [7]

Answer: mass

Explanation: the protons and neutrons make up the nucleus and nearly the entire mass of the atom

5 0
3 years ago
Select the keyword or phrase that will best complete each sentence. must undergo addition because they have easily broken tt bon
STatiana [176]

Alkenes must undergo addition because they have easily broken tt bonds.

Markonikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.

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Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.

In hydroboration, the boron atom bonds to the substituted carbon.

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8 0
3 years ago
What characteristic of gases makes them different from liquids or solids?
Marrrta [24]
<span>The particles are far apart from each other.</span>
5 0
3 years ago
What is the equilibrium constant of pure water at 25°C?
ANEK [815]
The equilibrium reaction, causes the water dissociation constant, Kw, is 1.01 × 10-14<span> at 25 °C. That is because every H</span>+<span> (H</span>3O+) ion these forms accompanied by the formation of an OH-<span> ion, are the concentrations of these ions and in pure water the same thing can be calculated from </span>Kw<span>. 

HOPED THIS HELP OUT ;)



</span>
6 0
3 years ago
Read 2 more answers
If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?
kvv77 [185]

Answer:

<h2>The answer is 14.29 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have

P(\%) =  \frac{0.1}{0.7}  \times 100 \\  = 14.285714...

We have the final answer as

<h3>14.29 %</h3>

Hope this helps you

4 0
4 years ago
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