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sertanlavr [38]
3 years ago
8

8. What is the frequency of green light waves that have a wavelength of 5.2 x 10-7 m.? The speed of light is 3.0 x 108 m/s

Physics
1 answer:
o-na [289]3 years ago
4 0

Answer:

f=5.76\times 10^{14}\ Hz

Explanation:

We need to find the frequency of green light having wavelength o5.2\times 10^{-7}\ m. It can be calculated as follows :

c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{5.2\times 10^{-7}}\\\\f=5.76\times 10^{14}\ Hz

So, the required frequency of green light is equal to 5.76\times 10^{14}\ Hz.

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Q1) After applying a force of 1000 N an object of mass 2000 kg will achieve what<br>acceleration?​
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Answer:

F=mass x acceleration

1000= 2000 x a

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a=1/2 m/sec^2

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3 years ago
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3 years ago
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Subtract the following numbers, using scientific notation and the correct number of significant digits.
tankabanditka [31]

Answer:

The correct answer is - 6.49 × 10^3 mm.

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The correct scientific notation of the given subtraction problem is:

6.94 × 10^3 mm - 4.5 × 10^2 mm = _____.

The correct number of significant digits is

a. 6.94 × 10^3 mm = 3

b. 4.5 × 10^2 mm = 2

So subtracting the 6.94 × 10^3 mm - 4.5 × 10^2 mm

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A meteor is falling towards the earth. If the mass and the radius of the earth are 6×10^24kg and 6.4×10^3km respectively,find th
Klio2033 [76]

Answer:

h = 3600 km

Explanation:

Given,

The mass of the Earth, M = 6 x 10²⁴ km

The radius of the Earth, R = 6.4 x 10³ km

The acceleration of the meteor at height, x = 4 m/s²

The acceleration due to gravity at the surface of the Earth is given by the formula,

                                    g = GM/R²

At height 'h' acceleration is given by the formula,

                                     gₓ = GM/Rₓ²

                                    Rₓ² =  GM/gₓ

                                          = 6.673 x 10⁻¹¹ X 6 x 10²⁴ / 4

                                          = 1 x 10¹⁴

                                       Rₓ = 1 x 10⁷ m

Where,

                                  Rₓ = R + x

                                   x = Rₓ - R

                                        = 10000 km - 6400 km

                                        = 3600 km

Hence, the height of the meteor where its acceleration due to gravity is 4 m/s² is, h = 3600 km

4 0
4 years ago
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