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kherson [118]
3 years ago
7

This problem has been solved!

Physics
1 answer:
dalvyx [7]3 years ago
8 0

Answer:

A. Workdone by helium, W = -1.829KJ

B. Internal energy, DE = 25.271KJ

Explanation:

Workdone can be defined as the force moving through a distance. For a gaseous system, when the volume of the gas expands, the system is losing energy. Therefore,

W = -P*DV

Where P is the pressure in pascal

DV is the change in volume in m3

DV = Vfinal - Vinitial

= 23.70 - 5.30

= 18.4L

W = -(0.981 * 18.4)

= -18.0504L.atm

Converting L.atm to joule,

= -18.0504 * 101.325

= -1828.97J

= -1.829KJ

If the system loses heat, Q the rection occurring is Exothermic.

Heat is the transfer of energy from one system to another.

Q = mcDT

Where m is the mass of the system

C is the specific heat capacity

Q = 27.20KJ

Internal energy is the summation of the heat supplied to a system and the workdone by the system

DE = Q + W

DE = 27.10 + (-1.829)

= 25.27KJ

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Answer: Nuclear fusion.

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It has six layers: The core, the radioactive zone, the convective zone, the photosphere, the chromosphere and the corona.

Magnetic field disruptions near active regions can generate strong explosions in the sun such as sun flashes and coronal mass ejections. The degree of complexity of the sun´s magnetic field increases and decreases with the course of each sunspot cycle.  

Sir Arthur Eddington was the first to evaluate all the data and dared to conjecture that nuclear fusion, the process that creates heavy elements from the fusion of lighter ones, could be responsible for the great production of the sun´s energy; this process make the sun´s energy was taken for the earth and the planet get back to the sun recycled energy. The sun has a very large and complex magnetic field; the average magnetic field of the sun is approximately 1 Gauss, almost twice as strong as the average magnetic field of the Earth´s surface (approximately 0.5 Gauss). Because the surface of the sun is more than 12.000 times larger than the Earth, the overall influence of the sun´s magnetic field is immensely large.

6 0
3 years ago
A railroad freight car of mass 3.34 × 104 kg collides with a stationary caboose car. They couple together, and 19.0% of the init
Tresset [83]

Answer:

4.123 * 10∧4 kg

Explanation:

mass of car M' = 3.34 * 10∧4 kg

energy loss E = 19/100  K

from law of conservation of momentum ,

                 M' V' = ( M' + M'' ) v

                        V = M' V' / ( M' + M'' )

       Initial kinetic energy is K'  = (M' V')² / 2

      final kinetic energy  K" = 81 K' /100

                                             =  (M' V')² 81 / (200)     =   ( M' + M'' ) v²/ 2

            therefore , M' / ( M' + M" ) = 0.81

 mass of caboose is ,  M" = 1.234 M' - M'

                                     M" = .234 M'

                                          = 0,234 ( 3.34 * 10∧4 kg)

                                          = 4.123 * 10∧4 kg

8 0
3 years ago
Which of the following quantities represent mass?
lisabon 2012 [21]

Answer:

Explanation:

a ) 12.0 lbs  -  mass

b ) .34 g   - mass

c ) 120 kg    - mass  

As lbs , g and kg are units of mass , these things represent mass . lbs is FPS unit of mass and kg is  SI unit . g is CGS unit of force .

d ) 1600 kN     It represents force because kN or kilonewton is unit of  force .

e ) it represents , length or distance because m or metre  is unit of length .

f ) 411 cm It represents length or distance because cm is smaller unit of length

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6 0
3 years ago
What is the mass of a bullet moving at 970m/s if the bullet’s KE is 3.9x 10^3J
motikmotik

Answer:

0.08kg

Explanation:

K.E = 1/2 mv^2

v = 970m/s

K.E = 3.9x 10^3J= 3900J

K.E = 1/2 mv^2

3900 = 1/2 m x 970x 970

3900 = 1/2 ×940900m

3900 = 470450m

m = 3900/470450 = 0.00828993516 = 0.008kg

4 0
3 years ago
Read 2 more answers
A rope of negligible mass passes over a uniform cylindrical pulley of 1.50 kg mass and 0.090 m radius. The bearings of the pulle
madreJ [45]

Answer:

1.8 m/s²

36 N

34.8 N

Explanation:

For the monkey :

m₁ = mass of monkey = 4.50 kg

T₁ = Tension force in the rope on monkey's side

a = acceleration

From the force diagram, force equation for the motion of monkey is given as

m₁ g - T₁ = m₁ a

(4.50 x 9.8) - T₁ = 4.5 a

T₁ = 44.1 - 4.5 a                                             eq-1

For the bunch of bananas :

m₂ = mass of bunch of bananas = 3 kg

T₂ = tension force in the rope on the side of banana

From the force diagram, force equation for the motion of bananas is given as

T₂ - m₂ g = m₂ a

T₂ - (3 x 9.8) = 3 a

T₂ = 29.4 + 3 a                                            eq-2

m = mass of the pulley = 1.50 kg

r = radius of the pulley = 0.090 m

α = angular acceleration of pulley = a/r

Torque equation for the pulley is given as

(T₁ - T₂ )r = I α

(T₁ - T₂ )r = I (a/r)

T₁ - T₂  = (0.5 m r²) (a/r²)

T₁ - T₂  = (0.5) ma

using eq-1 and eq-2

44.1 - 4.5 a  - (29.4 + 3 a) = (0.5) ma

44.1 - 4.5 a  - (29.4 + 3 a) = (0.5) (1.50) a

a = 1.8 m/s²

Using eq-1

T₁ = 44.1 - 4.5 a    

T₁ = 44.1 - 4.5 (1.8)    

T₁ = 36 N

using eq-2

T₂ = 29.4 + 3 a

T₂ = 29.4 + 3 (1.8)

T₂ = 34.8 N

7 0
3 years ago
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