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Alona [7]
3 years ago
12

Tas watches as his uncle changes a flat tire on a car. His uncle raises the car using a machine called a jack. Each time his unc

le pushes down on the jack handle, the car rises up. Tas sketches the jack and labels it using the symbols F, to represent force, and d, to represent distance. He uses large and small letters to compare the sizes of the forces and distances. Which set of labels is correct for the side of the jack that Tas’s uncle pushes on?
Physics
2 answers:
Xelga [282]3 years ago
5 0

Answer:

choice 4

Explanation:

Monica [59]3 years ago
3 0
The correct label would be: small f and capital D.

The car jack is an example of a machine, which is defined as anything that a person can use to make the exertion of force easier. So with the small force he exerts on the jack, the distance that the car is lifted up increases.
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Answer: x ≈ 36.3 cm

Explanation:

Conservation of momentum during the collision

0.0340(120) + 1.24(0) = (0.0340 + 1.24) v

v = 3.2025 m/s

The kinetic energy of the block/bullet mass will convert to spring potential

½kx² = ½mv²

x = √(mv²/k)

x = √(1.274(3.2025²) / 99.0)

x = 0.363293... ≈ 36.3 cm

3 0
3 years ago
(11) The speed of radio waves is 300 000 000 m/s.
Neko [114]

Answer:

Wavelength = 9.68 meters

Explanation:

Given the following data;

Speed = 300,000,000m/s

Frequency = 31 Megahertz to Hertz = 31 * 10⁶ Hz

To find the wavelength;

Wavelength = speed/frequency

Wavelength = 300,000,000/31,000,000

Wavelength = 9.68 meters

7 0
3 years ago
The near point of an eye is 110 cm. A corrective lens is to be used to allow this eye to focus clearly on objects 26.0 cm in fro
irga5000 [103]

Answer:

The focal length of the lens is 34.047 cm

The power of the needed corrective lens is 2.937 diopter.

Explanation:

Distance of the object from the lens,u = 26 cm

Distance of the image from the lens ,v= -110 cm

(Image is forming on the other side of the lens)

Since ,lens of the human eye is converging lens,convex lens.

Using a lens formula:

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{26 cm}+\frac{1}{-110 cm}

f = 34.047 cm = 0.3404 m

Power of the lens = P

P=\frac{1}{f}=\frac{1}{0.34047 m}=2.937 diopter

6 0
3 years ago
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Fantom [35]
Momentum is simply a quantity that measures the impact of a moving body over something is due to the mass it posseses or the velocity with which it is moving. Mathematically,ut is the product of mass and velocity of a body. It is represented by capital p...(P) P=mv Solution to the problem: we know P=mv For mass,eliminate m from the equation, m=P/v Put values, m=5000/5=1000kg
8 0
3 years ago
A 5000 g toy car starts from rest and moves a distance of 300 cm in 3 s under the action of a single constant force. Determine t
sveticcg [70]

Answer:

3.33 N

Explanation:

First, find the acceleration.

Given:

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4 0
3 years ago
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