Answer:
Correct answer: Yes, with acceleration a = 10 m/s²
Explanation:
By definition acceleration is equal.
a = ΔV / Δt = (V₂ - V₁) / (t₂ - t₁)
a = (10 - 0)/ (1 - 0) = (20 - 10)/ (2 - 1) = ........ (50 - 40)/ (5 -4) = 10 m/s²
a = 10 m/s²
God is with you!!!
Answer:
v(t) = s′(t) = −9sin(t)+9cos(t)
a(t) = v′(t) = −9cos(t) −9sin(t)
Explanation:
Given that
s = 9 cos(t) + 9 sin(t), t ≥ 0
Then acceleration and velocity is
v(t) = s′(t) = −9sin(t)+9cos(t)
a(t) = v′(t) = −9cos(t) −9sin(t)
<u>Answer:</u> The specific heat of ice is 2.11 J/g°C
<u>Explanation:</u>
When ice is mixed with water, the amount of heat released by water will be equal to the amount of heat absorbed by ice.
The equation used to calculate heat released or absorbed follows:
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
......(1)
where,
q = heat absorbed or released
= mass of ice = 12.5 g
= mass of water = 85.0 g
= final temperature = 22.24°C
= initial temperature of ice = -15.00°C
= initial temperature of water = 25.00°C
= specific heat of ice = ?
= specific heat of water = 4.186 J/g°C
Putting values in equation 1, we get:
![12.5\times c_1\times (22.24-(-15))=-[85.0\times 4.186\times (22.24-25)]](https://tex.z-dn.net/?f=12.5%5Ctimes%20c_1%5Ctimes%20%2822.24-%28-15%29%29%3D-%5B85.0%5Ctimes%204.186%5Ctimes%20%2822.24-25%29%5D)
Hence, the specific heat of ice is 2.11 J/g°C
I'm pretty sure that you have mass. When it comes to gravity, anything that has mass behaves exactly like anything else that has mass. Any two of them are attracted to each other, with a force that's proportional to the product of their masses, and inversely proportional to the square of the distance between them.
Now, if you have mass, then you have weight ... it's the answer you give when somebody asks "How much do you weigh ?". That's the force of gravity between you and the Earth, pulling you toward the center of the Earth. But it doesn't stop there. There's also a force of gravity pulling the Earth toward the center of you. The strength of it is EQUAL to your weight.
Your weight on Earth is EQUAL to the Earth's weight on YOU !
