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jok3333 [9.3K]
4 years ago
7

I need this fast thank you❣️

Physics
2 answers:
mel-nik [20]4 years ago
7 0
The rule for the sequence is: You add 4/6 each time
5/6 +4/6 = 1 1/2
1 1/2 + 4/6 = 2 1/6
2 1/6 +4/6 = 2 5/6
muminat4 years ago
3 0
The rule is that 4/6 is added each time, and when adding or subtracting a fraction the denominator stays the same
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A 4.55 nF parallel-plate capacitor contains 27.5 μJ of stored energy. By how many volts would you have to increase this potentia
aivan3 [116]

Answer:

\Delta V=V_{2}-V_{1}=45.4V

Explanation:

The energy, E, from a capacitor, with capacitance, C, and voltage V is:

E=\frac{1}{2} CV^{2}

V=\sqrt{2E/C}

If we increase the Voltage, the Energy increase also:

V_{1}=\sqrt{2E_{1}/C}

V_{2}=\sqrt{2E_{2}/C}

The voltage difference:

V_{2}-V_{1}=\sqrt{2E_{2}/C}-\sqrt{2E_{1}/C}

V_{2}-V_{1}=\sqrt{2*55*10^{-6}/4.55*10^{-9}}-\sqrt{2*27.5*10^{-6}/4.55*10{-9}}=45.4V

5 0
3 years ago
What is a concave lens?
ozzi
A concave lens is a lens that has at least one of its surfaces or both surfaces curved inwards. Due to this reason, this lens diverges the light that falls on it and hence is also called a diverging lens. The concave lens is thinner in the middle compared to its edges. These are used in flashlights, binoculars, telescopes, etc.
Please see attached image for reference.

5 0
3 years ago
A single slit of width 0.3 mm is illuminated by a mercury light of wavelength 254 nm. Find the intensity at an 11° angle to the
MArishka [77]

Answer:

The  the intensity at an 11° angle to the axis in terms of the intensity of the central maximum is  

   I_c = \frac{I}{I_o}  =8.48 *10^{-8}

Explanation:

From the question we are told that

   The  width of the slit is  D  =  0.3 \ mm =  0.3 *10^{-3} \ m

    The  wavelength is  \lambda =  254 \ nm =  254 *10^{-9} \ m

     The angle is  \theta  =  11^o

The intensity of at 11^o to the axis in terms of the intensity of the central maximum. is mathematically represented as

        I_c = \frac{I}{I_o}  = [ \frac{sin \beta  }{\beta }] ^2

Where \beta is mathematically represented as

        \beta  =  \frac{D sin (\theta ) *  \pi}{\lambda }

substituting values

      \beta  =  \frac{0.3 *10^{-3} sin (11 ) * 3.142}{254 *10^{-9} }

     \beta  =  708.1 \ rad

So

  I_c = \frac{I}{I_o}  = [ \frac{sin (708.1)  }{(708.1)}] ^2

   I_c = \frac{I}{I_o}  =8.48 *10^{-8}

6 0
4 years ago
Consider a brick that is totally immersed in water, with the long edge of the brick vertical. the pressure on the brick is
Gemiola [76]
The bottom . I hope thats the answer you looking for. Let me know
7 0
4 years ago
A car with a mass of 2,000 kg travels at 20 m/s. Which one has the greatest impulse?
sasho [114]

Answer:2000kg

Explanation:

Convert it

4 0
3 years ago
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