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Lilit [14]
3 years ago
14

Write the equality and conversion factors for the relationship between miles and hours for a car traveling at 55 mi/h

Physics
1 answer:
AysviL [449]3 years ago
5 0

Using Raoult’s Law, we can calculate for the vapor pressure using the formula:

P = x * P(pure)

Where x is the mole fraction of water, P(pure) = pressure of pure water, P = pressure when in solution

calculating for mole fraction of water:

x = (0.42kg / 18kg/kmol) / ((0.42kg / 18kg/kmol) + (0.075kg / 192.12kg/kmol))

x = 0.9835

Therefore:

P = 0.9835* P(71.93 mmHg)

<span>P = 70.75 mmHg</span>

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1.) The object's Velocity

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When a wire loop is connected to a battery, what is produced in the loop?
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As SCUBA divers go deeper underwater, the pressure from the weight of all the water above them increases tremendously which comp
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Answer: A.

As a diver rises, the pressure on their body decreases which allows the volume of the gas to decrease.

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The problem is that a diver, experiences an increased pressure of water compresses nitrogen and more of it dissolves into the body. Just as there is a natural nitrogen saturation point at the surface, there are saturation points under water. Those depend on the depth, the type of body tissue involved, and also how long a diver is exposed to the extra pressure. The deeper a diver go, the more nitrogen the body absorbs.

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4 0
3 years ago
Explain what causes something to be a magnet
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Read 2 more answers
A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2
ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}

And we need to find out the change in momentum of the body . Here ,

  • velocity before collision (u) = 10m/s
  • velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

\sf\longrightarrow momentum (p)= mass(m) * velocity(v)

Therefore change in momentum will be,

\sf\longrightarrow \triangle p = mv - mu

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\

\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s)  \\

\sf\longrightarrow \Delta p   = 0.1 kg * -12m/s \\

\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\

7 0
2 years ago
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