V = 1¹/₃πr³
V = 1¹/₃(3.14)(2)³
V = 1¹/₃(3.14)(8)
V = 1¹/₃(25.12)
V ≈ 33.493 in³
Answer:
A
Step-by-step explanation:
Answer:
the awnser is 10
Step-by-step explanation:
because it just is
Answer:
For covering 
unit area of the entire playground, the amount of sand required is equal to volume of 
buckets of sand.
Step-by-step explanation:
Given -
volume of sand in bucket is able to cover 
area of the entire playground
Thus,
For covering unit area of the entire playground, the amount of sand required is equal to of the total volume of sand in bucket
For covering unit area of the entire playground, the amount of sand required is equal to
For covering unit area of the entire playground, the amount of sand required is equal to volume of buckets of sand.
The above question is incomplete.
Complete Question
Minor arc KL measures 135°. Circle O is shown. Line segments K O and O L are radii. Which is the radian measure of central angle KOL?
a) StartFraction 3 pi Over 8 EndFraction radians
b) StartFraction 3 pi Over 4 EndFraction radians
c) StartFraction 7 pi Over 8 EndFraction radians
d) StartFraction 13 pi Over 5 EndFraction radians
Answer:
b) StartFraction 3 pi Over 4 EndFraction radians
Step-by-step explanation:
Minor arc KL measures 135°. Circle O is shown. Line segments K O and O L are radii.
Note that:
π radians = 180°
Therefore,
180° = π radians
135° = x
Cross Multiply
180° × x = 135° × π radians
x = 135° × π radians/180
x = 3π/4 radians
Therefore, the radian measure of central angle KOL is 3π/4 radians. Option b) is the correct option.
