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PilotLPTM [1.2K]

3 years ago

15

What are the electric fields at the positions ( x, y ) = ( 5.0 cm , 0cm ) , (−5.0 cm, 5.0 cm) and (−5.0 cm, −5.0 cm)? Write each

electric field vector in component form.

1 answer:

shepuryov [24]3 years ago

6 0

Answer:

The other missing details in the question; A +10 nC charge is located at the origin.

Explanation:

The detailed step by step calculation and appropriate substitution is as shown in the attachment.

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What stress would shift the equilibrium position of the following system to the left?

Margarita [4]

Answer:

Heating the system

Explanation:

According to the principle of Le Chatelier, for a system at equilibrium, a specific disturbance would make the equilibrium shift toward the direction which minimizes such a disturbance.

Since we wish to shift the equilibrium to the left, this means we wish to increase the concentration of products, as an excess in their concentration would make the products react and produce more reactants in order to lower the excess concentration of products.

Since heat is also a product, an increase in heat would shift the equilibrium toward the left, as this would consume the excess of heat by producing the reactants.

4 0

3 years ago

A(n) _____ is an organic compound that contains a nitrogen atom bonded to one, two, or three carbon atoms.

Katyanochek1 [597]

Tertiary Amine

The reason Why it is Tertiary Amine is because it has three carbons and one nitrogen.

7 0

3 years ago

Read 2 more answers

If the reaction N2 (g) + 3 H2 (g) --> 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo

Luba_88 [7]

<u>Answer:</u> The value of $K_c$ is 0.136 and is reactant favored.

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

The expression for the $K_{c}$ is given as:

$K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}$

We are given:

$[NH_3]=0.25M$

$[H_2]=0.75M$

$[N_2]=1.1M$

Putting values in above equation, we get:

$K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}$

$K_c=0.135$

There are 3 conditions:

When $K_{c}>1$ ; the reaction is product favored.
When $K_{c}$ ; the reaction is reactant favored.
When $K_{c}=1$ ; the reaction is in equilibrium.

For the given reaction, the value of $K_c$ is less than 1. Thus, the reaction is reactant favored.

Hence, the value of $K_c$ is 0.136 and is reactant favored.

4 0

3 years ago

Which element is capable of forming long chains by forming single, double, or triple bonds with itself?

gayaneshka [121]

Catenation is the property by which it can make bonds with other carbon<span> atoms to form long chains. Hence, </span>carbon<span>, with the least diffuse valence shell p orbital is capable of forming longer p-p sigma bonded chains of atoms than heavier elements which bond via higher valence shell orbitals.</span>

5 0

3 years ago

Read 2 more answers

A solution with [ OH] of 5 x 10-3 has a pH of

CaHeK987 [17]

Answer:

11·699

Explanation:

Given the concentration of hydroxide ion in the solution is 5 × $10^{-3}$ M

Assuming the temperature at which it is asked to find the pH of the solution be 298 K

<h3>At 298 K the dissociation constant of water is $10^{-14}$ </h3><h3>∴ pH + pOH = 14 at 298 K</h3><h3>pOH of the solution = -log( concentration of hydroxide ion )</h3>

∴ pOH of the given solution = - log(5 × $10^{-3}$ = -0·699 + 3 = 2·301

pH of the given solution = 14 - 2·301 = 11·699

∴ pH of the solution = 11·699

8 0

3 years ago