Answer:
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Answer:
<u>= 2.2 g pf S. produced</u>
Explanation:
Balanced Reaction equation:
→ 
1 mole of H2S - 34.1g
? moles - 3.2g
= 3.2/34.1 =<u> 0.09 moles of H2S</u>
Also,
1 mole of S02 - 64.07 g
? moles - 4.42g
= 4.42/64.07 <u>= 0.069 moles of SO2</u>
<u />
<em>Meaning SO2 is the limiting reagent</em>
Finally, 3 moles of S - 32g of sulphur
0.069 mole = ? g of Sulphur
= 0.069 x 32
<u>= 2.2 g pf S.</u>
Answer:
volume of 
Explanation:
Firstly balance the given chemical equation,

From the given balance equation it is clearly that,
2 mole of Li gives 1 mole of H2 gas
⇔
⇔
⇔
hence
3 mole of Li will give 1.5 mole H2 gas
therefore volume of gas produced from 3 mole Li at 
volume of H2=33.6 litre