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tresset_1 [31]
3 years ago
10

The half-life of carbon-14 is about 6000 years. assume that a sample of charcoal is formed by burning of living wood 15,000 year

s ago. how much of the original carbon-14 would remain today?
Chemistry
1 answer:
zimovet [89]3 years ago
4 0
The daughter isotope has an atomic number one less than the parent and a mass number two less. : A. : 1 20) The half-life<span> of </span>carbon-14<span> is about </span>6000 years<span>. </span>Assume<span> that a </span>sample<span> of </span>charcoal formed<span> by</span>burning<span> of </span>living wood 15,000 years ago<span>. How </span>much<span> of the </span>original carbon-14 would remain today? A) more than one-<span>half</span>
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Answer:

616,0 ng is the right answer.

Explanation:

You should know that 1 mole = 1 .10^9 nanomoles

Get the rule of three.

1 .10^9 nanomoles ...................... 56.0 gr

11 nanomoles .....................

(11 x 56) / 1 .10^9 nanomoles = 6.16 x 10^-7 gr

Let's convert

6.16 x 10^-7 gr x 1 .10^9 = 616 ngr

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Answer:

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Explanation:

What Adi failed to realize is that the oily substance that was obtained from lavender consists of a mixture of substances. It is not only the required  fragrance that is present in the extract.

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Hence the experiment will not work because; if some kind of separation method is not used to identify other impurities in the oil, many other substances may be mistaken for the actual fragrance.

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