(NEED HELP ASAP)

One atom of an element A =6.644 *10^-23 gm. calculate the no. of gram atom in 80 kg of it.

Oksana_A [137]

Answer:

5.3152*10^-24

Explanation:

3 0

4 years ago

Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting e

seropon [69]

Answer:

C2H3Br + O2 → CO2 + H2O + HBr

Explanation:

The term balancing of chemical reaction equation has a unique meaning in chemistry. What it actually means is to ensure that the number of atoms of each element on the left hand side of reaction equation becomes equal to the number of atoms of the same element on the right hand side of the reaction equation.

When we look at the equation; C2H3Br + O2 → CO2 + H2O + HBr, the number of atoms of each element on the left and right hand sides of the given equation are not the same hence the equation is unbalanced.

If we look at the equation; 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr, the number of atoms of each element on both sides of the reaction equation are now equal, thus the later equation is the balanced version of the former.

6 0

3 years ago

How do you classify a metal

Alenkinab [10]

Answer:

They are solid (with the exception of mercury, Hg, a liquid).

They are shiny, good conductors of electricity and heat.

They are ductile (they can be drawn into thin wires).

They are malleable (they can be easily hammered into very thin sheets).

If this satisfies you please consider giving me brainliest :)

8 0

3 years ago

Suppose 650 mL of hydrogen gas are produced through a displacement reaction involving solid iron and sulfuric acid, H2SO4, at ST

scoray [572]

Answer:

4.415 g of FeSO₄

Explanation:

The balance chemical equation for given single replacement reaction is as follow;

Fe + H₂SO₄ → FeSO₄ + H₂

Data Given;

Volume = 650 mL = 0.65 L

Density at STP = 0.08988 g/L

Mass = Density × Volume = 0.08988 g/L × 0.65 L = 0.0584 g

Step 1: Calculate Moles of H₂ as;

Moles = Mass / M.Mass

Moles = 0.0584 g / 2.01 g/mol

Moles = 0.0290 mol of H₂

Step 2: Find out moles of FeSO₄ as;

According to balance chemical equation,

1 mole of H₂ is produced along with = 1 mole of FeSO₄

So,

0.0290 moles of H₂ will be produced along with = X moles of FeSO₄

Solving for X,

X = 0.0290 × 1 mol / 1 mol

X = 0.0290 moles of FeSO₄

Step 3: Calculate mass of FeSO₄ as;

Mass = Moles × M.Mass

Mass = 0.0290 mol × 151.90 g/mol

Mass = 4.415 g of FeSO₄

4 0

3 years ago

In an extraction experiment similar to your expt. 4, you attempt to separate 2-naphthol from cyclohexane, both of which are diss

Viktor [21]

Answer:

[a]. 108 mL.

[b].

1. use HCL in washing for the neutralization of NaOH.

2. Wash with water.

3. make use of MgSO4 to remove water traces.

4. Evaporate to get the pure cyclohexane

Explanation:

The chemical equation for the reaction between 2-naphthol and Sodium hydroxide is given below as:

C₁₀H₈O + NaOH --------------------------------------------------> C10H7O⁻ Na⁺ + H₂O.

The C10H7O⁻ Na⁺ is the aqueous phase.

The molarity of Sodium Hydroxide is = [ (mass of sodium hydroxide ) ÷ molar mass sodium hydroxide × volume] × 1000.

The molarity of sodium hydroxide = [ (5/40) × 100] × 1000 = 1.25 M.

The number of moles of 2-naphthol = mass / molar mass = 20 / 144.17 = 0.138 moles.

Recall that, the formula for the number of moles = concentration × volume. Therefore, the volume of sodium hydroxide is given below as:

Volume of sodium hydroxide = the number of moles of sodium hydroxide ÷ concentration of sodium hydroxide = 0.138 ÷ 1.25 = 0.108L = 108 mL.

In order to efficiently isolate relatively pure cyclohexane from the ether layer, the following process must be followed:

1. use HCL in washing for the neutralization of NaOH.

2. Wash with water.

3. make use of MgSO4 to remove water traces.

4. Evaporate to get the pure cyclohexane

7 0

4 years ago