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2 years ago

(NEED HELP ASAP)

Chemistry

1 answer:

zheka24 [161]2 years ago

8 0

1&3 are the answers lmk if it’s wrong

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How many mL of 2.0 M KOH are necessary to neutralize 50 mL of 1 M HCl?

worty [1.4K]

Answer:

25mL

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this can help you. Have a nice day!

6 0

3 years ago

Which of the following best describes an example of applied chemistry?

hram777 [196]

Answer:

Explanation:

Examples of applied chemistry include creation of the variety of laundry detergents on the market and development of oil refineries.

4 0

2 years ago

If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol

Lelu [443]

<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

$P_{1}V_{1}=P_{2}V_{2}$

Where,

P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

$V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L$

Remember, 1 L is equal to 1000 mL.

So,

$125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L$

So, calculating the new volume, we have:

$P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm$

Hence, the new pressure is 1.67 atm.

Have a nice day!

7 0

3 years ago

HELP ME PLEASE!!!!

liq [111]

Answer:

1.D

2.A

3.C

4.A

Explanation:

6 0

3 years ago

Read 2 more answers

What is the empirical formula of a compound that is made of 3.80g of phosphorus and 0.371g of hydrogen?

lys-0071 [83]

You start by diving each quantity given by the atomic wight of each element:

Phosphorus (P) $\frac{3.8}{31} =0.123$

Hydrogen (H) $\frac{0.371}{1} =0.371$

Then you divide by the lowest number:

$\frac{0.123}{0.123} = 1$ for phosphorus

$\frac{0.371}{0.123} = 3$ for hydrogen

So the empirical formula will be:

$PH_{3}$

6 0

3 years ago