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3 years ago

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(NEED HELP ASAP)

1 answer:

zheka24 [161]3 years ago

8 0

1&3 are the answers lmk if it’s wrong

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Law of Conservation of Mass in terms of atoms

VARVARA [1.3K]

No atoms are lost or made during the chemical reaction so the total mass of the products is equal to the total mass of the reactants. In an atom, protons and neutrons contribute to the mass and since the number of them doesn’t change, the mass doesn’t either.

4 0

3 years ago

Of the following which element is the heaviest? helium argon lithium aluminum

Georgia [21]

Answer:

Lithium

Explanation:

it is the only metal listed.

5 0

3 years ago

The air bags in cars are inflated when a collision triggers the explosive, highly exothermic decomposition of sodium azide (NaN3

Oksanka [162]

Answer : The mass of $NaN_3$ required is, 166.4 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $N_2$ gas = 1.00 atm

V = Volume of $N_2$ gas = 113 L

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $85^oC=273+85=358K$

Putting values in above equation, we get:

$1.00atm\times 113L=n\times (0.0821L.atm/mol.K)\times 358K$

$n=3.84mol$

Now we have to calculate the moles of sodium azide.

The balanced chemical reaction is,

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced reaction we conclude that

As, 3 mole of $N_2$ produced from 2 mole of $NaN_3$

So, 3.84 moles of $N_2$ produced from $\frac{2}{3}\times 3.84=2.56$ moles of $NaN_3$

Now we have to calculate the mass of $NaN_3$

$\text{ Mass of }NaN_3=\text{ Moles of }NaN_3\times \text{ Molar mass of }NaN_3$

Molar mass of $NaN_3$ = 65 g/mole

$\text{ Mass of }NaN_3=(2.56moles)\times (65g/mole)=166.4g$

Therefore, the mass of $NaN_3$ required is, 166.4 grams.

3 0

3 years ago

The periodic table is organized left to right by __________.

Romashka [77]

Answer:

Metals, metalloids, non-metals

Explanation:

:)

3 0

3 years ago

Read 2 more answers

What is the hydrogen ion concentration in a 0.10M solution of KOH?

dybincka [34]

KOH is a strong base, so [OH-] = 0.10 M = 1.0 x 10^-1 M

[H+][OH-] = Kw

Kw = 1.0 x 10^-14

[H+] = 1.0 x 10^-14 / 1.0 x 10^-1 = 1.0 x 10^-13 M

7 0

3 years ago