<span>Answer: 0.00649M
The question is incomplete,
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<span>You are told that the first ionization of the sulfuric acid is complete and the second ionization of the sulfuric acid has a constant Ka₂ = 0.012
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<span>
With that you can solve the question following these steps"
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<span>1) First ionization:
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<span>
H₂SO₄(aq) --> H⁺ (aq) + HSO₄⁻ (aq)
Under the fully ionization assumption the concentration of HSO4- is the same of the acid = 0.01 M
2) Second ionization
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<span>HSO₄⁻ (aq) ⇄ H⁺ + SO₄²⁻ with a Ka₂ = 0.012
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<span>Do the mass balance:
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<span><span> HSO₄⁻ (aq) H⁺ SO₄²⁻</span>
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<span /><span /><span> 0.01 M - x x x
</span><span>Ka₂ = [H⁺] [SO₄²⁻] / [HSO₄⁻]</span>
<span /><span>
=> Ka₂ = (x²) / (0.01 - x) = 0.012
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<span>3) Solve the equation:
</span><span>x² = 0.012(0.01 - x) = 0.00012 - 0.012x</span>
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x² + 0.012x - 0.0012 = 0
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<span>Using the quadratic formula: x = 0.00649
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<span>So, the requested concentratioN is [SO₄²⁻] = 0.00649M</span>
One Ba2+ and two Br- ions will be there.
Answer is 3
The element X is titanium.
According to the question, the percentage by mass of Cl in XCl4 is 75.0%.
The percentage by mass is obtained from;
Mass of element in the compound/molar mass of compound * 100
Hence;
Let the mass of the unknown element be X
75 = 142/X + 142 * 100
75 (X + 142) = 142 * 100
75X + 10650 = 14200
75X = 14200 - 10650
X = 14200 - 10650/75
X = 47
Hence, X is titanium.
Learn more; brainly.com/question/1363167
Answer:
obtain (food or provisions)
Explanation:
example: a girl foraging grass for oxen
Answer:
Explanation:
Given that:-
Moles of K = 1.10 moles
Moles of Te = 0.55 moles
Moles of O = 1.65 moles
Taking the simplest ratio of the moles of the elements as:-
K : Te : O
1.10 : 0.55 : 1.65
2 : 1 : 3
Empirical formulas is the simplest or reduced ratio of the elements in the compound. So, the empirical formula is:-
