Question

Two very quick questions!!

Answer 1

The weight lifted by a machine to the applied force on a machine is called mechanical advantage. This is written as Mechanical advantage, M. A, = load(weight)/effort. So for 1) M.A = 2 and load = 2, 000lb = 8896.446N. So 2 = 8896.446/ effort Effort = 8896.446/2 = 4448.48 Similarly for M.A of 2, 000, 000 we have Effort = 8896.446/ 2, 000, 000 = 0.004448

Answer 2

Explanation:

1. Mechanical advantage of a pulley system, m = 2

Mechanical advantage of a machine is defined as the ratio of load to the effort force i.e.

$m=\dfrac{F_L}{F_E}$

Here, $F_L=2000\ lb$

$F_E=\dfrac{F_L}{m}$

$F_E=\dfrac{2000\ lb}{2}$

$F_E=1000\ lb$

Hence, 1000 lb effort will be needed to move the car.

2. Mechanical advantage of a pulley system, m = 2,000,000

Value of load, $F_L=2000\ lb$

Mechanical advantage, $m=\dfrac{F_L}{F_E}$

$F_E=\dfrac{F_L}{m}$

$F_E=\dfrac{2000\ lb}{2000000}$

$F_E=0.001\ lb$

Hence, 0.001 lb effort would be needed to move the car.