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ch4aika [34]
3 years ago
12

Two very quick questions!!

Physics
2 answers:
stepladder [879]3 years ago
8 0
<span>The weight lifted by a machine to the applied force on a machine is called mechanical advantage. This is written as Mechanical advantage, M. A, = load(weight)/effort. So for 1) M.A = 2 and load = 2, 000lb = 8896.446N. So 2 = 8896.446/ effort Effort = 8896.446/2 = 4448.48 Similarly for M.A of 2, 000, 000 we have Effort = 8896.446/ 2, 000, 000 = 0.004448</span>
lana [24]3 years ago
5 0

Explanation:

1. Mechanical advantage of a pulley system, m = 2

Mechanical advantage of a machine is defined as the ratio of load to the effort force i.e.

m=\dfrac{F_L}{F_E}

Here, F_L=2000\ lb

F_E=\dfrac{F_L}{m}

F_E=\dfrac{2000\ lb}{2}

F_E=1000\ lb

Hence, 1000 lb effort will be needed to move the car.

2. Mechanical advantage of a pulley system, m = 2,000,000

Value of load, F_L=2000\ lb

Mechanical advantage, m=\dfrac{F_L}{F_E}

F_E=\dfrac{F_L}{m}

F_E=\dfrac{2000\ lb}{2000000}

F_E=0.001\ lb

Hence, 0.001 lb effort would be needed to move the car.

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