The spring constant of the spring if it would compress by 1 m to stop the ore car is 340,350.4 N/m.
<h3>
Potential energy of the car</h3>
The potential energy of the car is calculated as follows;
P.E = mgh
where;
- h is the vertical height of the incline
sin (10) = h/L
h = L x sin(10)
P.E = mgLsin(10)
P.E = 2000 x 9.8 x 50 x sin(10)
P.E = 170,175.21
<h3>Conservation of energy</h3>
The potential energy of the car at the top of the incline will be converted to the elastic potential energy spring at the bottom of the incline.
P.E = U = ¹/₂kx²
k = (2U)/x²
k = (2 x 170,175.2)/(1)²
k = 340,350.4 N/m
Learn more about spring constant here: brainly.com/question/1968517
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Answer:
40 gm
Explanation:
size one is 1/3 of size 3
so the mass is also 1/3
1/3 * 120 gm = 40 gm
Answer: El trabajo realizado al desplazar el bloque es: 75 N.m
Datos:
Fuerza= F= 25 N
Distancia= d= 3 m
Explicación:
El trabajo es el producto de la fuerza ejercida sobre un cuerpo con el desplazamiento producido por la fuerza. Para que exista trabajo, la dirección de la fuerza debe ser igual a la dirección del desplazamiento.
Trabajo= Fuerza x Desplazamiento
Reemplazando los datos:
T= 25 N * 3 m
T= 75 N.m
Dividing x^3 - 3x^2 - 4x + 12 by x + 2 gives
x^2 -5x + 6
= (x - 3)(x - 2)
so remaining factors are x - 3 and x - 2 answer
Answer:
EMF = 187.5 volts
Explanation:
As per Faraday's law of electromagnetic induction we know that rate of change in the flux will induce EMF
so we can say
now we will have
So the induced EMF in the coil will be 187.5 Volts