The volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .
<h3>Weight of one gallon of water</h3>
The weight of 1 gal of water is given as 3785 g
Mass of 8.48 x 10⁸ gal = 3785 x 8.48 x 10⁸ = 3.2 x 10¹² g
<h3>Volume of the water in cubic meters</h3>
Volume = mass/density
Volume = 3.2 x 10¹² g/1 gmL
Volume = 3.2 x 10¹² mL x 10⁻⁶ m³/mL = 3.2 x 10⁶ m³
Thus, the volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .
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Answer:
Sodium (Na) has atomic number 11.
Answer: 0.52 L of 15 M 
will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
Answer: The correct answer to this question is B because thats
what it states and says
Explanation:
Answer:
Number of moles = 0.75 mol
Mass = 118.5 g
Explanation:
Given data:
Number of moles of KMnO₄ = ?
Mass in gram = ?
Molarity of KMnO₄ = 0.25 M
Volume of KMnO₄ solution = 3 dm³ (3 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles / L of solution
0.25 M = number of moles / 3 L
Number of moles = 0.25 M× 3 L
M = mol/L
Number of moles = 0.75 mol
Mass in gram:
Mass = number of moles × molar mass
Mass = 0.75 mol × 158 g/mol
Mass = 118.5 g
