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Aleksandr-060686 [28]
3 years ago
5

A zoo is planning a new building for the penguin exhibit First they made a model that was 1.3 meters tall Then they made a more

detailed model that was 1.5 times as the first model The building will be 2.5 times as tall as the height of the detailed model What will be the height of the building
Mathematics
2 answers:
Brrunno [24]3 years ago
8 0
1.3x1.5x2.5= 4.875m is the height
Gala2k [10]3 years ago
6 0
Are u missing any parts I feel like ur miss what he got
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Complete the inequality statement.<br><br> 8 ___ 8<br><br> &gt;<br> &lt;<br> =
murzikaleks [220]

Answer:

8 = 8

Step-by-step explanation:

If the numbers are the same, they are equal ( = )

7 0
2 years ago
What is the product of (4x-7)(4x+7)?
miskamm [114]
(a+b)(a-b)=a^2 - b^2
so

<span>(4x-7)(4x+7) = 16x^2 - 49

answer
</span>16x^2 - 49
6 0
3 years ago
I will give brainliest
Natasha_Volkova [10]

Answer:

  • 225°
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  • reference angle of 45°

Step-by-step explanation:

585-360= 225

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3 0
3 years ago
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Given a soda can with a volume of 36 and a diameter of 4, what is the volume of a cone that fits perfectly inside the soda can?
spin [16.1K]
First we need to find the heigh of the soda can be rearanging the volume formula, . We can make that  We know that V is 36 and radius is half of the diameter, so radius is 2. 

h = 2.87

Now, we can use the height to figure out the volume of a cone. The volume of a cone is 
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So a cone with a volume of 12.0576 is the largest that will fit into the soda can
6 0
3 years ago
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HELP ME PLESA IM DESPO PAKJDCD PLS HELP
WARRIOR [948]

Answer:

144 cm²

Step-by-step explanation:

A prism's surface has 2 triangles & 3 rectangles.

In both the triangles , length of :

Perpendicular = 4 cm

Base = 6 cm

So , Area of both triangles = 2(\frac{1}{2} * Base * Perpendicular) = 2(\frac{1}{2}* 6 * 4) = 24 cm^2

In the 3 rectangles ,

Length = 8 cm

Width = 5 cm

So , Area of the rectangles = 3( Length * Width) = 3(8 * 5) = 120 cm^2

Hence the total surface area of the prism is = 120 + 24 =144 cm²

6 0
2 years ago
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