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4 years ago

Which conclusion could be made from Ernest Rutherford’s gold foil experiment?

2 answers:

5 0

The conclusion was that there must be space between the particles of an atom. The way he knew this is because while some of the radiation reflected off of the gold foil, other radiation went right through it.

Katarina [22]4 years ago

5 0

Answer:

Mass of an atom is concentrated in a positively charged core called the nucleus.

Explanation:

Rutherford gold foil experiment expanded our understanding of the structure of an atom. When positively charged alpha particles were bombarded against a thin gold foil, Rutherford observed that majority of particles passed through the foil undisturbed whereas a small percentage retraced their path.

There were two main conclusions from the experiment:

-Since most alpha particles simply passed through undeviated this suggested that majority of the space inside the atom is empty

- Also, since some of them completely bounced back this suggested that there is a positively charged core in which the mass of the nucleus is concentrated.

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Given the following cations, list them in the expected order from smallest to largest: Y3+, Nb3+, Sb3+

Ugo [173]

Answer: Antimony ion is the smallest and yttrium ion is the largest.

Explanation:

Atomic radius of an atom is defined as the total distance from the nucleus to the outermost shell of the atom.

An ion is formed when a neutral atom looses or gains electrons.

When an atom looses electrons, it results in the formation of positive ion known as cation.
When an atom gains electrons, it results in the formation of negative ion known as anion.

As moving from left to right in a period, more and more electrons get added up in the same shell and the attraction between the last electron and nucleus increases, which results in the shrinkage of size of an atom. Hence, the size of an atom decreases.

The size of the cation is small then their neutral atom because it has less number of electrons while its nuclear charge remains the same. Thus, the nucleus attracts the electron more towards itself and leads to the decrease in size.

We are given three cations: $Y^{3+},Nb^{3+}\text{ and }Sb^{3+}$

Yttrium lies in Period 5, group 3 of the periodic table.

Niobium lie in Period 5, group 5 of the periodic table.

Antimony lies in Period 5, group 15 of the periodic table.

So, the order of atomic radii in increasing order follows:

$Sb^{3+}$

Hence, antimony ion is the smallest and yttrium ion is the largest.

6 0

3 years ago

How many different types of elements are there in acetone C3H6O?

Ymorist [56]

Answer:

Explanation:

5 0

4 years ago

Read 2 more answers

What is the highest occupied energy level for an atom of copper (Cu)? *

bonufazy [111]

Answer:

third energy level - 18

hope this helps

8 0

3 years ago

The activity of tocopherols is destroyed by

grandymaker [24]

A. Commercial cooking

3 0

4 years ago

How many moles are in 123.0g (NH4)2SO4

Luda [366]

Here you go! There are 0.9307 moles in 123.0 g of the compound. I solved this by using a fence post method. I calculated the number of grams in one mol of (NH4)2 SO4 and got 132.16.

I did this by finding the atomic mass of each element on the periodic table (my work is in the color blue for this step)

After that, i divided the given mass by the mass of one mol of the compound.

The answer is 0.9307 moles!! I hope this helped you! :))

7 0

3 years ago