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3 years ago

Which conclusion could be made from Ernest Rutherford’s gold foil experiment?

2 answers:

5 0

The conclusion was that there must be space between the particles of an atom. The way he knew this is because while some of the radiation reflected off of the gold foil, other radiation went right through it.

Katarina [22]3 years ago

5 0

Answer:

Mass of an atom is concentrated in a positively charged core called the nucleus.

Explanation:

Rutherford gold foil experiment expanded our understanding of the structure of an atom. When positively charged alpha particles were bombarded against a thin gold foil, Rutherford observed that majority of particles passed through the foil undisturbed whereas a small percentage retraced their path.

There were two main conclusions from the experiment:

-Since most alpha particles simply passed through undeviated this suggested that majority of the space inside the atom is empty

- Also, since some of them completely bounced back this suggested that there is a positively charged core in which the mass of the nucleus is concentrated.

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What are they waiting? or what are their waiting? please correct me if I'm wrong

kiruha [24]

Hm I’m confused, if you mean what are they weighting, it’s they :)

3 0

2 years ago

Why chlorine is more reactive than hydrogen

Lynna [10]

Answer:

Hi Todoroki here!!!

Explanation:

Chlorine has the electron configuration [Ne]3s 2 3p 5, with the seven electrons in the third and outermost shell acting as its valence electrons. Like all halogens, it is thus one electron short of a full octet, and is hence a strong oxidising agent, reacting with many elements in order to complete its outer shell.

Your welcome!!

7 0

3 years ago

Relation between glancing and angle of deviation

shtirl [24]

Answer:

the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.

5 0

2 years ago

Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction

11Alexandr11 [23.1K]

Answer:

Balanced equation:

$Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)$

Explanation:

The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.

$Lead(II)Nitrate+Potassium\,carbonate \rightarrow Lead(III)\,\,carbonate+Potassium\,nitrate$

$Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)$

Ionic equation:

$Pb^{2+}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)+K^{+}(aq)+2NO_{3}^{-}$

Cancel the same ions on the both sides of the reaction.

The net ionic equation is as follows.

$Pb^{2+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)$

4 0

2 years ago

What is the wavelength (in nm) of

LenKa [72]

Answer:

λ = 0.45×10⁻⁶ m

Explanation:

Given data:

Wavelength of blue light = ?

Frequency of blue light = 6.69×10¹⁴ s⁻¹

Solution:

Formula;

Speed of wave = wavelength × frequency

Speed of wave = 3.00×10⁸ m/s

by putting vales,

3.00×10⁸ m/s = λ × 6.69×10¹⁴ s⁻¹

λ = 3.00×10⁸ m/s / 6.69×10¹⁴ s⁻¹

λ = 0.45×10⁻⁶ m

6 0

2 years ago