2N2 Hy 03 2N₂²_0₂ +42 H₂O

Which two conditions must exist in order for radiation to occur?

melomori [17]

Answer:Which condition must exist in order for conduction to occur between two substances? The molecules of the substances must be touching. Both substances must be the same temperature. At least one substance must be a liquid.

Explanation:

7 0

3 years ago

A 10 N board of uniform density is 5 meters long. It is supported on the left by a string bearing a 3 N upward force. In order t

NikAS [45]

Answer:

C. $\frac{25}{7}$ m

Explanation:

We are given that

Weight of board=w=10 N

Length of board=L=5 m

Tension in the string=T=3 N

Applied upward force=F=7 N

We have to find the distance at which its left wedge would they need to place this force in order for the board to be in static equilibrium.

Let r be the distance at which its left wedge would they need to place this force in order for the board to be in static equilibrium.

The board is uniform therefore, the center of board is the mid- point of board.

Therefore, the lever arm of weight= $r_1=\frac{L}{2}=\frac{5}{2}m$

Now, the torque exerted by the weight of the board

$\tau_1=Force\times perpendicular\;distance=10\times \frac{5}{2}=25 N$

The torque exerted by applied force= $\tau_2=7\times r=7r$

In static equilibrium

The sum of rotational forces=0

$\tau_1+\tau_2=0$

The two rotational force act in opposite direction therefore,

$\tau_2=-7r$

Substitute the values

$25-7r=0$

$7r=25$

$r=\frac{25}{7}$ m

Hence, option C is true.

7 0

3 years ago

Two stationary positive point charges, charge 1 of magnitude 3.25 nC and charge 2 of magnitude 2.00 nC , are separated by a dist

Liula [17]

Complete Question

Two stationary positive point charges, charge 1 of magnitude 3.25 nC and charge 2 of magnitude 2.00 nC , are separated by a distance of 58.0 cm . An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges.

Required:

What is the speed of the electron when it is 10.0 cm from the +3.25-nC charge?

Answer:

The velocity is $v = 80.82 \ m/s$

Explanation:

From the question we are told that

The magnitude of charge one is $q_1 = 3.25 nC = 3.25 *10^{-9} \ C$

The magnitude of charge two $q_2 = 2.00 \ nC = 2.00 *10^{-9} \ C$

The distance of separation is $d = 58.0 \ cm = 0.58 \ m$

Generally the electric potential of the electron at the midway point is mathematically represented as

$V = \frac{ q_1 }{\frac{d}{2} } + \frac{ q_2}{\frac{d}{2} }$

substituting values

$V = \frac{ 3.25 *10^{-9} }{\frac{ 0.58}{2} } + \frac{ 2 *10^{-9} }{\frac{ 0.58}{2} }$

$V = 1.8103 *10^{-8} \ V$

Now when the electron is 10 cm = 0.10 m from charge 1 , it is (0.58 - 0.10 = 0.48 m ) m from charge two

Now the electric potential at that point is mathematically represented as

$V_1 = \frac{q_1}{ 0.10} + \frac{q_2}{ 0.48}$

substituting values

$V_1 = \frac{3.25 *10^{-9}}{ 0.10} + \frac{2.0*10^{-9}}{ 0.48}$

$V_1 = 3.67*10^{-8} \ V$

Now the law of energy conservation ,

The kinetic energy of the electron = potential energy of the electron

i.e $\frac{1}{2} * m * v^2 = [V_1 - V]* q$

where q is the magnitude of the charge on the electron with value

$q = 1.60 *10^{-19} \ C$

While m is the mass of the electron with value $m = 9.11*10^{-31} \ kg$

$\frac{1}{2} * 9.11 *10^{-19} * v^2 = [ (3.67 - 1.8103) *10^{-8}]* 1.60 *10^{-19}$

$v = \sqrt{6532.4}$

$v = 80.82 \ m/s$

4 0

3 years ago

Which of the following does Archimedes' principle help to explain?

irina1246 [14]

Which of the following does Archimedes' principle help to explains

O

C. Surface tension

6 0

3 years ago

Read 2 more answers

Bowling balls can be made from a variety of substances and are required to have a circumference of roughly 27.2 inches. The cons

Daniel [21]

Answer:

The bowlling shell's thickness is 2.7"

Explanation:

The geometry of the problem is based in the differences between the volumes in a small sphere and a spherical shell, both objects compose the total volume of the bowling ball.

The equivalence in the total ball height and the equivalent height in the fluid (in this case water displacement of half ball volume) is used for calculating the forces state that allows the static balance of the ball and the flotation force from the fluid (Archimedes principle).

In the image is showed the formulation.

4 0

4 years ago