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Snezhnost [94]
4 years ago
5

Which factor affects elastic potential energy but not gravitational potential energy?

Physics
2 answers:
julsineya [31]4 years ago
6 0

Explanation:

The energy stored in an elastic objects as a result of deformation is called elastic potential energy. The energy stored in a spring is given by :

E=\dfrac{1}{2}kx^2

Where

k = spring constant

x = compression or stretching in an spring

While gravitational potential energy is given by :

PE = mgh

where

m = mass

g = acceleration due to gravity

h = height from ground

So, the factor affecting elastic potential energy but not gravitational potential energy is " spring constant ".

anyanavicka [17]4 years ago
3 0

Answer:

spring constant  or C

Explanation:

if this helped please leave a thanks and go friend me if it did.

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Describe the direction in which each object will accelerate. If the object won't accelerate, write "no
pychu [463]

Answer:

The object will accelerate in the upward direction.

Explanation:

To know the direction in which the object will accelerate, we shall determine the net force acting on the object. This can be obtained as follow:

Upward force (Fᵤ) = 300 N

Downward force (Fₔ) = 200 N

Net force (Fₙ) =?

Fₙ = Fᵤ – Fₔ

Fₙ = 300 – 200

Fₙ = 100 N upward

Thus, the net force acting on the object is 100 N in the upward direction. This implies that the object will accelerate in the upward direction because the net force acting on the object is in the upward direction.

7 0
3 years ago
Selection of raffle tickets from a large bowl is an example of
deff fn [24]

subjective probability

4 0
4 years ago
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You should always measure your following distance in __________
HACTEHA [7]
You should always measure your following distance in FEET
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4 years ago
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A skier starts at the top of a very large, frictionless snowball, with a very small initial speed, and skis straight down the si
dangina [55]

Answer:

The answer to the question is

At the instant she loses contact with the snowball, the angle (alpha) a radial line from the center of the snowball to the skier make with the vertical is 48.2 °

Explanation:

At the point where the skier loses contact with the snpwball we have the centripetal force given by

m·g·cos θ - N = m\frac{v^2}{R}

Where  N = 0 at the point the skier leaves the snowball

That is

 m·g·cos θ  = m\frac{v^2}{R}

The height from which the skier drops from the snowball is given by

h = r - r·cosθ

Therefore the potential energy of the skier just before leaveing the snowball is

m·g·h = m·g·r·(1-cosθ)

From conservation of energy, the total energy of the skier is constant which means that is the potential energy is transformed to kinetic energy of the form

PE = KE That is  

\frac{1}{2} mv^2 = m·g·r·(1-cosθ) or

m\frac{v^2}{R} = 2·m·g·(1-cosθ) Howerver since   m·g·cos θ  = m\frac{v^2}{R} then we have

m·g·cos θ  = 2·m·g·(1-cosθ)  which gives

cosθ = 2·(1-cosθ) or 3·cosθ = 2

or cosθ =  \frac{2}{3} and θ = cos^{-1}\frac{2}{3} = 48.1896851 °

≈48.2 °

7 0
4 years ago
Justin notices a particular type of caterpillar feeds only on cottonwood trees in his neighborhood in which way has Justin
mixer [17]

The observation made by Justin about the caterpillar type feeding specifically over cottonwood tree (natural world) helped Justin to acquire scientific knowledge.

Answer: Option A

<u>Explanation: </u>

And it was observed that the specific caterpillar only fed on the cottonwood tree. Therefore, the inference was made based on the observation only and no experimentation was done from Justin.

The given set of method depicts the observational experiment as Justin notices and acquires the set pattern of the specific caterpillar. The object was to notice the specific caterpillar to see what it’s feeding on and whether it is feeding on other or not. So, it indicates the world's nature.

3 0
3 years ago
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