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inna [77]
3 years ago
12

Help please, how are the electrons and bonds represented in a lewis dot diagram?

Chemistry
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

Lewis dot diagrams use dots arranged around the atomic symbol to represent the electrons in the outermost energy level of an atom

Explanation:

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Give the percent yield when 162.8 g of CO2 are formed from the reaction of excess amount of
Zepler [3.9K]

Answer:

84.86%

Explanation:

Step 1:

We'll begin by writing a balanced equation for the reaction between C8H18 and O2 to produce CO2. This is illustrated below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Step 2:

Now, let us calculate the mass of O2 that reacted and the mass of CO2 produced from the balanced equation above. This is illustrated below:

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 25 x 32 = 800g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 16 x 44 = 704g

Therefore the mass of O2 that reacted from the balanced equation is 800g

The mass of CO2 produced from the balanced equation is 704g

Step 3:

Determination of the theoretical yield of CO2. This is illustrated below:

From the balanced equation above,

800g of O2 reacted to produced 704g of CO2.

Therefore, 218g of O2 will react to produce = (218 x 704)/800 = 191.84g of CO2.

Therefore, the theoretical yield of CO2 is 191.84g

Step 4:

Determination of the percentage yield of CO2. This is illustrated below:

Actual yield = 162.8g

Theoretical yield = 191.84g

Percentage yield =?

Percentage yield = Actual yieldm/Theoretical yield x100

Percentage yield = 162.8/191.84 x100

Percentage yield = 84.86%

Therefore, the percentage yield of CO2 is 84.86%

6 0
3 years ago
Read 2 more answers
How many moles are in 40.0g of CO​2
34kurt

Answer:0.90889467046888

Explanation:

7 0
3 years ago
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What determines the average kinetic energy of the particles in a gas? A. the number of collisions B. the number of particles C.
viktelen [127]

The answer is The Temperature

4 0
3 years ago
Read 2 more answers
Potential energy is based on an objects <br><br> A)gravity<br> B)mass<br> C)position <br> D)kinetic
ollegr [7]

Answer:

c

Explanation:

because potential energy is created with the position of a body when you pick up something the thing will have stored energy which is transferred from you so the stored energy is potential energy created by the position of a body that when you see over your head you scared of that thing not to bit you because it has stored energy if you see the thing already failed on the ground you wouldn't scared of that because the enery is already gone

Hope help you

5 0
3 years ago
"An aqueous CaCl2 solution has a vapor pressure of 83.1mmHg at 50 ∘C. The vapor pressure of pure water at this temperature is 92
Lynna [10]

Answer : The the concentration of CaCl_2 in mass percent is, 41.18 %

Solution : Given,

Molar mass of water = 18 g/mole

Molar mass of CaCl_2 = 110.98 g/mole

First we have to calculate the mole fraction of solute.

According to the relative lowering of vapor pressure, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component of the solution multiplied by the vapor pressure of that component in the pure state.

\fac{p^o-p_s}{p^o}=X_B

where,

p^o = vapor pressure of the pure component (water) = 92.6 mmHg

p_s = vapor pressure of the solution = 83.1 mmHg

X_B = mole fraction of solute, (CaCl_2)

Now put all the given values in this formula, we get the mole fraction of solute.

\fac{92.6-83.1}{92.6}=X_B

X_B=0.102

Now we have to calculate the mole fraction of solvent (water).

As we know that,

X_A+X_B=1\\\\X_A=1-X_B\\\\X_A=1-0.102\\\\X_A=0.898

The number of moles of solute and solvent will be, 0.102 and 0.898 moles respectively.

Now we have to calculate the mass of solute, (CaCl_2) and solvent, (H_2O).

\text{Mass of }CaCl_2=\text{Moles of }CaCl_2\times \text{Molar mass of }CaCl_2

\text{Mass of }CaCl_2=(0.102mole)\times (110.98g/mole)=11.32g

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O

\text{Mass of }H_2O=(0.898mole)\times (18g/mole)=16.164g

Mass of solution = Mass of solute + Mass of solvent

Mass of solution = 11.32 + 16.164 = 27.484 g

Now we have to calculate the mass percent of CaCl_2

Mass\%=\frac{\text{Mass of}CaCl_2}{\text{Mass of solution}}\times 100=\frac{11.32g}{27.484g}\times 100=41.18\%

Therefore, the the concentration of CaCl_2 in mass percent is, 41.18 %

4 0
3 years ago
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