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sdas [7]
3 years ago
11

Find the mass in 3.8 moles of magnesium chloride​

Chemistry
1 answer:
lisov135 [29]3 years ago
5 0

Explanation:

34.31+35.45(2)=

27.31+70.90=

95.21g/mol

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For the aqueous solution containing 75 mg of compound C in 1.0 mL of water, what will be the total amount of the solute C that w
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Answer:

75 mg

Explanation:

We can write the extraction formula as

x = m/[1 + (1/K)(Vaq/Vo)], where

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K = distribution coefficient

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Vaq = volume of aqueous layer

Data:

m = 75 mg

K = 1.8

Vo = 0.90 mL

Vaq = 1.00 mL

Calculations:

For each extraction,

1 + (1/K)(Vaq/Vo) = 1  + (1/1.8)(1.00/0.90) = 1 + 0.62 = 1.62  

x = m/1.62 = 0.618m

So, 61.8 % of the solute is extracted in each step.

In other words, 38.2 % of the solute remains.

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r = m(0.382)^n.

If n = 7,

r = 75(0.382)^7 = 75 × 0.001 18 = 0.088 mg

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After seven extractions, 75 mg (99.999 %) of the solute will be extracted.

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You performed an experiment to find out how far three different sizes of
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