Explanation:
Final velocity=Initial velocity+(acceleration×time)
4 ways to find initial velocity:
1) Initial velocity=Final velocity-(acceleration×time)
2) Initial velocity=(Distance/Time)-((acceleration×time)/2)
3) Initial velocity=√Final velocity-(2×(acceleration×distance))
4) Initial velocity=2(distance/time)-Final velocity
Total force = Mass×Acceleration
(F=ma)
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Answer:
19.53 cm
Explanation:
The computation of the height is as follows:
Here we applied the conservation of the energy formula
As we know that
P.E of the block = P.E of the spring
m g h = ( 1 ÷ 2) k x^2
where
m = 0.15
g = 9.81
k = 420
x = 0.037
So now put the values to the above formula
(0.15) (9.81) (h) = 1 ÷2 × 420 × (0.037)^2
1.4715 (h) = 0.28749
h = 0.19537 m
= 19.53 cm
Answer:
102900 Joules
Explanation:
Assuming the kinetic energy was zero at the moment of release, you can make the following argument to solve the problem:
The potential energy at full height was mgh. We are told that after 70% of the distance, i.e., mg(0.3h) = 44.1kJ. Since potential energy is linear in altitude h, we get get the full potential energy to be 44.1kJ/0.3. The difference between full potential energy and the one after 70% of the way must equal the gained kinetic energy (neglecting stuff like heat due to friction). So,
44.1kJ/0.3 - 44.1kJ = 0.7*44.1kJ/0.3 = 102.9kJ = Ekinetic
The kinetic energy after 70% of the falling distance was 102.9 kJ.