Answer:
the movement of airflow and how its processed in the greenhouse
Explanation:
Answer:
Explanation:
A )
v² = u² + 2 a s
u = 0
s = 2.5
a = 9.8
v² = 2 x 9.8 x 2.5 = 49
v = 7 m /s
B )
time required to fall by first 2.5 m , t₁
s = 1/2 a t₁²
2.5 = .5 x 9.8 t₁²
t₁ = .714 s
time required to fall by 10 m
s = 1/2 a t₂²
10 = .5 x 9.8 t₂²
t₂ = 1.43 s
time required to fall by last 7.5 m
= t₂ - t₁
= 1.43 - .714
= .72 s
C )
time taken by second = .72 s
For second let initial velocity required be u
s = ut + 1/2 g t²
10 = u x .72 + .5 x 9.8 x .72²
10 = u x .72 + 2.54
u = 10.36 m /s
The work you put into something is the energy it has afterward (neglecting friction and other so-called non-conservative forces). This is called the work-energy theorem. Think of objects in a gravitational field as "energy piggy banks". If you put X joules of energy into it, that energy will be there as potential energy, stored for later. So if you do 144J of work to elevate the bucket from an initial position, what ever it is initially, the final gravitational energy is 144J greater than before.
Explanation:
Given , F = 30N and mass m = 90kg
°•° F = ma
=> a = F/m
=> a = 30/90
=> a = 1/3m/s^2
Answer:
The current density is
The drift velocity is
Explanation:
From the question we are told that
The nominal diameter of the wire is
The current carried by the wire is
The power rating of the lamp is
The density of electron is
The current density is mathematically represented as
Where A is the area which is mathematically evaluated as
Substituting values
So
The drift velocity is mathematically represented as
Where e is the charge on one electron which has a value
So