Answer:
2 m/s and -2 m/s
Explanation:
The object travels with an angle of
60.0°
with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).
If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:
If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:
<span>The law of conservation of matter and energy relates to the cycles in nature, and by that it is also applied to rocks and other materials. All of the rock in the Earth is recycled and accounted for during the rock cycle. Rocks experience physical change, the composition of the material stays the same, it may just change how it looks and chemical changes occur (the suubstance undergoes a chemical reaction that changes the actual makeup of the substance).</span>
An estimated value for gravity at a distance r from the middle of the Earth can be gotten by supposing that the Earth's density is spherically symmetric. The gravity hinge on only on the mass inside the sphere of radius r. All the assistances from outside cancel out as a fall out of the inverse-square law of gravitation. Another result is that the gravity is the same as if all the mass were concentrated at the midpoint. Therefore, the gravitational acceleration at this radius is
g(r) = GM(r) / r²
M(r) = mass enclosed by radius r.
If the Earth had a continual density ρ, the mass would be M(r) = (4/3)πρr³ and the dependence of gravity on distance would be
g(r) = (4/3)πGρr
G = 6.674e-11 m³/kgs²
Answer:
1) as far as I remember
Let's take 20 as vf (final velocity) and 11 as (initial velocity) and 4 as time
So we would use this formula a=vf-vi/t
So 20-11/4
Asnwer 2.25
