Number of moles ( n ) = ?
Volume ( V ) = 0.25 L
Molarity of solution ( M ) = 2.00 M
n = M x V
n = 2.00 x 0.25
n = 0.5 moles of Ba(NO₃)₂
hope this helps!
If bubbles aren't a for sure way of knowing a chemical reaction I don't know what is. But being for real, it is a chemical change because the bubbles are releasing carbon dioxide meaning it turned into a product from a reaction with outside forces.
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Answer:
answer is in exaplation
Explanation:
Answer. Chemical reaction had occurred and both the powders are different substances.
Explanation:
As density is an intensive property of the substance.Which means that different substance have different densities.
Density = \frac{mass}{volume}
volume
mass
Density of powder 1, d_1=\frac{0.5g}{45cm^3}=0.11g/cm^3d
1
=
45cm
3
0.5g
=0.11g/cm
3
Density of powder 2, d_2=\frac{1.3g}{65cm^3}=0.02g/cm^3d
2
=
65cm
3
1.3g
=0.02g/cm
3
On comparing both the densities of the powders we can say that both the substances are different. So we can conclude that the chemical reaction had occurred.
Answer:
Explanation:
Let the tyrosine molecule be represented by TH . It will ionise in water as follows
TH ⇄ T⁻ + H⁺
Let C be the concentration of undissociated TH and α be the degree of dissociation
TH ⇄ T⁻ + H⁺
c 0 0 ( before )
c( 1-α ) αc αc ( after ionisation)
Ka = α²c² / c( 1-α )
= α²c ( neglect α in the denominator as it is very small )
pKa = 10
Ka = 10⁻¹⁰
pH = 8.5
H⁺ = 10⁻⁸°⁵
αc = 10⁻⁸°⁵
α²c =Ka = 10⁻¹⁰
α x10⁻⁸°⁵ = 10⁻¹⁰
α = 10⁻¹⁰⁺⁸°⁵
= 10⁻¹°⁵ = 1 / 31.62
Percentage of dissociation = 100 / 31.62
= 3.16 %
percent of tyrosine side chains deprotonated
