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Sholpan [36]
3 years ago
9

Can some one please help me with this organic chemistry question?

Chemistry
1 answer:
const2013 [10]3 years ago
4 0
I think it is gauche.

I know the angle between two atoms in equatorial positions is 60 degrees. and 60 degrees is seen in gauche conformations.
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Argon (Ar) and helium (He) are initially in separate compartments of a container at 25°C. The
love history [14]

Answer:

(a) V_B=11.68L

(b) x_{He}=0.533

Explanation:

Hello,

In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:

n_A=\frac{0.082\frac{atm*L}{mol*K}*298K}{1.974 atm*6.00L}=2.063mol

Thus, since the final pressure is 3.60 bar, we can write:

P=x_{Ar}P_A+x_{He}P_B\\\\P=\frac{n_{Ar}}{n_{Ar}+n_{He}} P_A+\frac{n_{He}}{n_{Ar}+n_{He}} P_B\\\\3.60bar=\frac{2.063mol}{2.063mol+n_{He}} *2.00bar+\frac{n_{He}}{2.063mol+n_{He}} *5.00bar

The moles of helium could be computed via solver as:

n_{He}=2.358mol

Or algebraically:

3.60bar=\frac{1}{2.063mol+n_{He}} *(4.0126+5.00*n_{He})\\\\7.314+3.60n_{He}=4.013+5.00*n_{He}\\\\7.314-4.013=5.00*n_{He}-3.60n_{He}\\\\n_{He}=\frac{3.3}{1.4}=2.358mol

In such a way, the volume of the compartment B is:

V_B=\frac{n_{He}RT}{P_B}=\frac{2.358mol*0.082\frac{atm*L}{mol*K}*298.15K}{4.935atm}\\  \\V_B=11.68L

Finally, he mole fraction of He is:

x_{He}=\frac{2.358}{2.358+2.063}\\ \\x_{He}=0.533

Regards.

8 0
2 years ago
What does the oxidation state of kr indicate
const2013 [10]
Kr look on periodic table it's krypton elements
8 0
3 years ago
What is the concentration of a 500 mL solution with 25 mol of HF? Write your answer with TWO decimal places and round accordingl
statuscvo [17]

Answer:

23

Explanation:

3 0
2 years ago
What is the volume of 0.120 g of C2H2F4<br> vapor at 0.970 atm and 22.4°C?<br> Answer in units of L.
ludmilkaskok [199]

Answer:

V= 0.031L

Explanation:

P= 0.97atm, V= ?, n= 0.12/98 =0.00122mol, R= 0.082, T= 22.4+273= 295.4

Applying

PV=nRT

0.970×V = 0.00122×0.082×295.4

Simplify the above equation

V= 0.031L

6 0
2 years ago
How many moles of a gas would occupy 22.4 Liters at 273 K and 1 atm?<br><br><br> Read bottom comment
Genrish500 [490]

Answer:

The following relationship makes this possible: 1 mole of any gas at standard temperature and pressure (273 K and 1 atm) occupies a volume of 22.4 L.

Explanation:

4 0
2 years ago
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