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zvonat [6]
3 years ago
9

According to Charles law when the temperature of a gas at constant pressure is increased it

Chemistry
1 answer:
Anestetic [448]3 years ago
5 0


According Charles law, when the temperature of a gas at constant pressure is increased, the volume of the gas increases.  The law states that for a mixed mass of a gas at constant pressure, the volume is directly proportional to the Kelvin temperature.

That is to say that if for example you double the Kelvin temperature from, say 400K to 600k, at  a constant pressure, the volume of a mixed mass of the gas will double as well.

Charles studied the compressibility of gases nearly 100 years  after  Boyle. In his experiments, he noted that at fixed pressure, the volume of a gas is proportional to the temperature of the gas.

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Assoli18 [71]
Answer: 5
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3 years ago
Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

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3 years ago
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c(HNO₂) = 0,075 M.
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This is buffer solution, so use <span>Henderson–Hasselbalch equation:
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pH = -log(4,5·10⁻⁵) + log(0,035 M ÷ 0,075 M).
pH = 4,35 - 0,33.
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3 years ago
Describe the main difference between the Bohr model and the electron cloud model of the atom
Leno4ka [110]

Answer:

The main difference between the two models is <em>the position of the electron in the atom</em>.

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3 years ago
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