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Nady [450]
3 years ago
11

What are things that we use that are on the periodic table

Chemistry
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

Here's the Real Life Use of Every Element on the Periodic Table

Hydrogen. Symbol: H. Atomic Weight: 1.008. ...

Magnesium. Symbol: Mg. Atomic Weight: 24.305. ...

Aluminum. Symbol: Al. Atomic Weight: 26.9815385. ...

Phosphorus. Symbol: P. Atomic Weight: 30.973761998(5) ...

Chlorine. Symbol: Cl. ...

Argon. Symbol: Ar. ...

Potassium. Symbol: K. ...

Calcium. Symbol: Ca.

Explanation:

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Consider the reaction mg(oh)2(s)→mgo(s)+h2o(l) with enthalpy of reaction δhrxn∘=37.5kj/mol what is the enthalpy of formation of
Anni [7]
Answer is: -601,2 kJ/mol
Chemical reaction: Mg(OH)₂ → MgO + H₂O.
ΔHrxn = 37,5 kJ/mol.
ΔHf(Mg(OH)₂) = <span>−924,5 kJ/mol.
</span>ΔHf(H₂O) = <span>−285,8 kJ/mol.
</span>ΔHrxn -enthalpy of reaction.
ΔHf - enthalpy of formation.
<span>ΔHrxn=∑productsΔHf−∑reactantsΔHf. 
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3 years ago
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what are the roles of minerals in maintaning homeostasis?

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2 years ago
Using the formula M1V1 = M2V2 , how many milliliters of a 2.50 M hydrochloric acid solution is required to make 100.0 mL of a 0.
olga nikolaevna [1]

30ml of a 2.50 M hydrochloric acid solution is required to make 100.0 mL of a 0.750 M solution.

<h3>What is HCl?</h3>

HCl is an acid which is made up of hydrogen and chlorine gas.

By the formula of dilution

M1V1 = M2V2

where V1 = 2.50 m

M2 = 100.0

V2 = 0.750 m

M1 × 2.50 m = 100.0 × 0.750 m

M1 = 30 ml

Thus, the M1 is 30 ml option a is correct.

Learn more about HCl

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A volatile liquid is one that ______?
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readily evaparates.


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7 0
3 years ago
A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4
balu736 [363]

Answer:

51.53 grams .

Explanation:

Na₃PO₄    ⇄  3Na⁺¹   +    PO₄⁻³ .

1 mole           3 mole

725 mL of 1.3 M Na⁺  ions

= .725 x 1.3 moles of Na⁺ ions

= .9425 moles

3 mole of Na⁺  is formed by 1 mole of Na₃PO₄

.9425 mole of Na⁺  is formed by .9425/3  mole of Na₃PO₄

Na₃PO₄ needed =  .9425/3  moles = .3142 moles

Molecular weight of Na₃PO₄ = 164

grams of Na₃PO₄ needed = .3142 x 164 = 51.53 grams .

8 0
2 years ago
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