How many water molecules would be produced in making a polypeptide that is 14 amino acids long?
2 answers:
water molecules would be produced in making a polypeptide that is 14 amino acids long.
Further Explanation:
The organic compounds that consist of an amine functional group, a carboxyl
functional group, and a side chain are known as amino acids. Different amino acids have different side chains. These compounds have carbon, hydrogen, nitrogen and oxygen atoms in them.
Two amino acids are joined to each other with the help of peptide bonds which are formed by the removal of water molecules by the interaction between the acids. This happens when the carboxyl group of one amino acid reacts with the amine group
of another amino acid. Since the formation of peptide bonds result in the removal of the water molecule, it is also called dehydration synthesis or a condensation reaction.
Polypeptides are linear chains of amino acids that are linked together by peptide or amide bonds. These are classified on the basis of their sources and function. Polypeptides are the building units for proteins.
Since one peptide bond is formed by the removal of one water molecule by the interaction of two amino acids, it is clear that the number of water molecules formed is one less than the number of amino acids present. So 14 amino acids would produce 13 water molecules.
Learn More:
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Answer Details:
Grade: Senior School
Chapter: Amino Acids
Subject: Chemistry
Keywords: amino acids, 13, water molecules, peptide bonds, polypeptide, proteins, building units.
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Answer:
The answer is below
Explanation:
A normal model is represented as (μ, σ). Therefore for (1.5, 0.18), the mean (μ) = 1.5 and the standard deviation (σ) = 0.18
The z score shows by how many standard deviations the raw score is above or below the mean. It is given as:
a) For x < 1.35 s
From the normal distribution table, the percent of drivers have a reaction time less than 1.35 seconds = P(x < 1.35) = P(z < -0.83) = 0.2033 = 20.33%
b) For x > 1.9 s
From the normal distribution table, the percent of drivers have a reaction time greater than 1.9 seconds = P(x > 1.9) = P(z > 2.22) = 1 - P(z<2.22) = 1 - 0.9868 = 0.0132 = 1.32%
c) For x = 1.45
For x = 1.75
From the normal distribution table, P(1.45 < x < 1.75) = P(-0.28 < z < 1.39) = P(z < 1.39) - P(z< - 0.28) = 0.9177 - 0.3897 = 0.528 = 52.8%
d) A percentage of 10% corresponds to a z score of -1.28
e) P(z < z1) - P(z< -z1) = 60%
P(z < z1) - P(z< -z1) = 0.6
P(z < -z1) = 1 - P(z < z1)
P(z<z1) - (1 - P(z < z1)) = 0.6
2P(z<z1) - 1= 0.6
2P(z<z1) = 1.6
P(z<z1) = 0.8
From the z table, z1 = 0.85
The reaction time between 1.35 and 1.65 seconds