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3 years ago

Where in water is being converted into a gaseous form?

Chemistry

1 answer:

puteri [66]3 years ago

7 0

Answer:

It's called Evaporation.

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What is the mass (in grams) of 3.03 × 1024 molecules of carbon dioxide molecules?

krek1111 [17]

1 mole of CO2 has 6.02 x 10^23 molecules of CO2. Say x moles of CO2 has 3.0x10^23 molecules of CO2. Therefore x = 3/6.02 = 0.50. M = 0.50 * (12 + 2x16) = 0.50 * 44 = 22g

5 0

3 years ago

How many protons (p), neutrons (n), and electrons (e) are in one atom of 23 12mg?

REY [17]

Djakdhsidhdudhebejrdhdd

7 0

3 years ago

Https://www.change.org/p/scholastic-bring-back-maya-and-miguel/dashboard?source_location=user_profile_started

charle [14.2K]

Answer:

I got it

Explanation:

Thank you friend

6 0

3 years ago

Read 2 more answers

We have 548 grams of CaCl2. How many molecules of CaCl2 do we have? (The molar mass of CaCl2 is 110.98 g/mol)

nekit [7.7K]

Answer:

Try everything

2.97 x 10^24 molecules

3.66 x 10^28 molecules

9.1 x 10^22 molecules

4.37 x 10^22 molecules

Explanation:

3 0

3 years ago

Express the concentration of a 0.0320 M aqueous solution of fluoride, F−, in mass percentage and in parts per million (ppm). Ass

denis23 [38]

Answer:

607 ppm

Explanation:

In this case we can start with the ppm formula:

$ppm=\frac{mg~of~solute}{Litters~of~solution}$

If we have a solution of 0.0320 M, we can say that in 1 L we have 0.032 mol of $F^-$ , because the molarity formula is:

$M=\frac{mol}{L}$

In other words:

$0.0320~M=\frac{mol}{1~L}$

$mol=0.032~M*1~L=0.032~mol$

$1~L~of~Solution=0.0320~mol~of~solute$

If we use the atomic mass of $F$ (19 g/mol) we can convert from mol to g:

$0.0320~mol~F^-\frac{19~g~F^-}{1~mol~F^-}~=~0.607~g$

Now we can convert from g to mg (1 g= 1000 mg), so:

$0.607~g\frac{1000~mg}{1~g}=607~mg$

Finally we can divide by 1 L to find the ppm:

$ppm=\frac{607~mg}{1~L}=~607~ppm$

We will have a concentration of 607 ppm.

I hope it helps!

4 0

4 years ago