Answer:
The final pressure of gas is 82.64 KNm⁻²
Explanation:
Given data:
Initial volume of gas = 180 cm³
Temperature of gas = 27°C
Initial pressure = 101 KNm⁻²
Final volume = 220 cm³
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
101 KNm⁻² × 180 cm³ = P₂
× 220 cm³
P₂ = 18180 KNm⁻². cm³/220 cm³
P₂ = 82.64 KNm⁻²
The final pressure of gas is 82.64 KNm⁻².
Answer : The amount of energy evolved during the reaction is, 
.
Solution : Given,
Mass of Al = 51.2 g
Molar mass of Al = 27 g/mole
First we have to calculate the moles of Al.
The balanced combustion reaction is,
From the given reaction, we conclude that
As, 2 moles of Al evolved energy = 
So, 1.896 moles of Al evolved energy = 
Therefore, the amount of energy evolved during the reaction is, .
Butane undergoes combustion to produce carbon dioxide and water, expressed in the following reaction <span> C4H10 (g) + O2 (g) → 4CO2 (g) + 5H2O (g) . 1 mole of butane is to 4 moles of CO2. In this case, when 22.8 grams of butane or 0.393 moles of it, 69.18 grams of carbon dioxide is produced</span>
Answer:
C. ElectricalElectrical
Explanation:
( it might be wrong pls dont report me just let me kno y its wrong )
Answer:
Explanation:
Step 1. Calculate the moles of C₁₂H₂₂O₁₁
Step 2. Calculate the mass of C₁₂H₂₂O₁₁
