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Grace [21]
3 years ago
5

Why does liquids rate of evaporation increase when the liquid is heated

Chemistry
1 answer:
ivann1987 [24]3 years ago
4 0
Boiling liquids that want to escape gas
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stellarik [79]

A.conduction  i hope it helps

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2 years ago
You will be reading from an essay and a play dealing with the lives of women in the late eighteenth and early
s344n2d4d5 [400]

Answer:

all work

Explanation:

6 0
3 years ago
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When the temperature of a sample of neon gas increases, what else increases? Distance between the atoms Kinetic energy of the at
Allushta [10]

Answer: Kinetic Energy of the atoms also increases.

Explanation: We are given that the temperature of the gas increases.

Relation between kinetic energy and temperature follows:

K.E._({avg})=\frac{3RT}{2N_A}

where, K = Average Kinetic energy

R = Gas constant

T = Temperature

N_A = Avogadro's number

As seen from the relation above, the Kinetic energy of the gas is directly proportional to the temperature, hence as the temperature increases, kinetic energy of the atom also increases.

4 0
3 years ago
How many moles of gold, Au, are in 3.60 x 10^-5 g of gold?
zlopas [31]
<h3>Answer:</h3>

1.83 × 10⁻⁷ mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.60 × 10⁻⁵ g Au (Gold)

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. Multiply:                            \displaystyle 1.82769 \cdot 10^{-7} \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

4 0
2 years ago
What would be the vapor pressure at 25.0 °c of a solution of 5.00 g of glucose (c6h12o6) in 100.0 g of ethanol (c2h5oh)?
Crank
Use Raoult's Law:
Psolution = (χsolvent) (P°solvent)

24.90 = (x) (25.756)

x = 0.966765 (this is the solvent mole fraction)

χsolute = 1 - 0.966765 = 0.033235

χsolute = 0.03324 (to four sig figs)
4 0
3 years ago
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