MgCl₂ & PbSO₄ is the correct product for the given double replacement reaction.
<h3>What is double displacement reaction?</h3>
In the double displacement reaction displacement of two substrate will take place among two reactants and formation of products takes place.
In the question, PbCl₂ reacts with MgSO₄ and displacement between the cations takes place and formation of MgCl₂ and insoluble precipitate PbSO₄ is formed.
Given reaction is represented as:
PbCl₂ + MgSO₄ → MgCl₂ + PbSO₄
According to the activity series, reactivity of Magnesium is more as compared to the lead atom. So lead is displaced by the magnesium atom and form the above given products.
Hence, option (3) is correct i.e. MgCl₂ & PbSO₄.
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Answer:
6
Explanation:
The maximum number of electrons in the orbitals of sub-levels are given as:
for s-sublevel we have two electrons and one orbital
p-sublevel we have six electrons and three orbitals
d-sublevel we have ten electrons and five orbitals
f- sublevel we have fourteen electrons and seven orbitals
The second energy level is represented by the p-sub-level and it will accommodate 6 electrons.
Ionic Bonds have a Lower melting and Covalent have higher.
Answer:
the correct answer is option A copper and silver