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AleksandrR [38]
3 years ago
15

Please help me feel in the blanks Giving 30 points

Physics
1 answer:
maw [93]3 years ago
7 0

4:chemical properties can only be observed when a substance changes into another substance.

5: physical properties such as color and shape are easy to observe

6: in a chemical change an altered substance forms

7: cooking or baking food will result in a chemical change

8: a melting ice cube is a physical change

9: the rusting of iron is a chemical change

10: water boiling is a scientific physical change

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The mesosphere is the coldest layer of the atmosphere. It is located above the stratosphere. 
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The number of organisms that can be sustained by an environment without environmental degradation is__________.
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carrying capacity.

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The number of organisms that can be sustained by an environment without environmental degradation is its carrying capacity.

The carrying capacity of a living species in an ecosystem is the species ' maximum population size that the environment could carry indefinitely, given the ecosystem's food, habitat, water, as well as other necessities are sufficient. 

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An example of a poor conductor of electricity is a
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Two particles with charges +6e and -6e are initially very far apart (effectively an infinite distance apart). They are then fixe
JulijaS [17]

Answer:

\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}\ J.

Explanation:

Given charges are:

\rm q_1 = +6e.\\q_2 = -6e.

The electric potential energy of a charge due to the electric field of another charge is given by

\rm EPE=\dfrac{kq_1q_2}{r}.

where,

  • k = Coulomb's constant, having value = \rm 9\times 10^9\ Nm^2/C^2.
  • r = distance between the charges.

When the charges are infinite distance apart, \rm r = \infty,

\rm EPE_{initial} = \dfrac{kq_1q_2}{r}=0\ J.

When the charges are \rm 5.61\times 10^{-12}\ m apart, \rm r=5.61\times 10^{-12}\ m,

\rm EPE_{final}=\dfrac{kq_1q_2}{r}\\=\dfrac{(9\times 10^9)\times (+6e)\times (-6e)}{5.61\times 10^{-12}}\\=-5.775\ e^2\times 10^{22}.

Here, e is the charge on one electron, such that, \rm e = -1.6\times 10^{-19}\ C.

Therefore,

\rm EPE_{final}=-5.775\times (-1.6\times 10^{-19})^2\times 10^{22} = -1.478\times 10^{-15}\ J.

Thus,

\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}-0=-1.478\times 10^{-15}\ J.

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3 years ago
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