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IgorC [24]
3 years ago
9

A balloon contains 269.7 L of helium at 6.12ºC and 1.00 atm. What is the temperature (in ºC) of the gas if the volume has increa

sed by 320.4 L at the same pressure?
Chemistry
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

T2= 7.3°C

Explanation:

To solve this problem we will use Charles law equation i.e,

V1/T1 = V2/T2    

Given data

V1 = 269.7 L

T1 = 6.12 °C

V2= 320.4 L

T2=?

Solution:

Now we will put the values in equation

269.7 L / 6.12°C  = 320.4 L / T2

T2=  320.4 L × 6.12°C/ 269.7 L

T2= 1960.85 °C. L /269.7 L

T2= 7.3°C

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Explain the regiochemical outcome for chlorination of bromobenzene.
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Answer:

See explanation

Explanation:

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In the chlorination of bromobenzene, ortho attack and para attack are preferred because each of these pathways involves a sigma complex with__4________resonance structures. Attack at the meta position involves formation of a sigma complex with only____3_______ resonance structures. The reaction will proceed more rapidly via the_____lower_______ energy sigma complex, so attack takes place at the ortho and para positions in preference to the meta position.

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What is the symbol of an ion with 16 protons, 18 neutrons, and 18 electrons? what is the symbol for an ion that has 16 pro-tons,
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3 0
3 years ago
An unknown gas contains 5.4 moles in 34 mL. If the amount of gas increases to 6.2 moles, what is the new volume?
Murljashka [212]

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.

<h3>What is Avogadro's law?</h3>

Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

It is expressed as;

V₁/n₁ = V₂/n₂

Given the data in the question;

  • Initial amount of gas n₁ = 5.4moles
  • Initial volume v₁ = 34mL = 0.034L
  • Final amount of gas n₁ = 6.2moles
  • Final volume v₂ = ?

We substitute our values into the expression above.

V₁/n₁ = V₂/n₂

V₁n₂ = V₂n₁

V₂ = V₁n₂ / n₁

V₂ = (0.034L × 6.2moles) / 5.4moles

V₂ = 0.2108molL / 5.4mol

V₂ = 0.039L

V₂ = 39 mL

Therefore, at constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.

Learn more about Avogadro's law here: brainly.com/question/15613065

#SPJ1

6 0
2 years ago
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